details

property	value
status	complete
benchmark	size-12-alpha-3-num-480.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n142.star.cs.uiowa.edu
space	Waldmann_07_size12

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	9.48626 seconds
cpu usage	33.5406
user time	32.135
system time	1.40558
max virtual memory	6.0603636E7
max residence set size	3814772.0

stage attributes

key	value
starexec-result	YES

output

32.90/9.35 YES 33.26/9.40 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 33.26/9.40 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 33.26/9.40 33.26/9.40 33.26/9.40 Termination w.r.t. Q of the given QTRS could be proven: 33.26/9.40 33.26/9.40 (0) QTRS 33.26/9.40 (1) QTRS Reverse [EQUIVALENT, 0 ms] 33.26/9.40 (2) QTRS 33.26/9.40 (3) DependencyPairsProof [EQUIVALENT, 2 ms] 33.26/9.40 (4) QDP 33.26/9.40 (5) QDPOrderProof [EQUIVALENT, 120 ms] 33.26/9.40 (6) QDP 33.26/9.40 (7) QDPOrderProof [EQUIVALENT, 172 ms] 33.26/9.40 (8) QDP 33.26/9.40 (9) DependencyGraphProof [EQUIVALENT, 0 ms] 33.26/9.40 (10) TRUE 33.26/9.40 33.26/9.40 33.26/9.40 ---------------------------------------- 33.26/9.40 33.26/9.40 (0) 33.26/9.40 Obligation: 33.26/9.40 Q restricted rewrite system: 33.26/9.40 The TRS R consists of the following rules: 33.26/9.40 33.26/9.40 a(a(x1)) -> a(b(b(c(x1)))) 33.26/9.40 c(a(x1)) -> x1 33.26/9.40 c(b(x1)) -> a(c(x1)) 33.26/9.40 33.26/9.40 Q is empty. 33.26/9.40 33.26/9.40 ---------------------------------------- 33.26/9.40 33.26/9.40 (1) QTRS Reverse (EQUIVALENT) 33.26/9.40 We applied the QTRS Reverse Processor [REVERSE]. 33.26/9.40 ---------------------------------------- 33.26/9.40 33.26/9.40 (2) 33.26/9.40 Obligation: 33.26/9.40 Q restricted rewrite system: 33.26/9.40 The TRS R consists of the following rules: 33.26/9.40 33.26/9.40 a(a(x1)) -> c(b(b(a(x1)))) 33.26/9.40 a(c(x1)) -> x1 33.26/9.40 b(c(x1)) -> c(a(x1)) 33.26/9.40 33.26/9.40 Q is empty. 33.26/9.40 33.26/9.40 ---------------------------------------- 33.26/9.40 33.26/9.40 (3) DependencyPairsProof (EQUIVALENT) 33.26/9.40 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 33.26/9.40 ---------------------------------------- 33.26/9.40 33.26/9.40 (4) 33.26/9.40 Obligation: 33.26/9.40 Q DP problem: 33.26/9.40 The TRS P consists of the following rules: 33.26/9.40 33.26/9.40 A(a(x1)) -> B(b(a(x1))) 33.26/9.40 A(a(x1)) -> B(a(x1)) 33.26/9.40 B(c(x1)) -> A(x1) 33.26/9.40 33.26/9.40 The TRS R consists of the following rules: 33.26/9.40 33.26/9.40 a(a(x1)) -> c(b(b(a(x1)))) 33.26/9.40 a(c(x1)) -> x1 33.26/9.40 b(c(x1)) -> c(a(x1)) 33.26/9.40 33.26/9.40 Q is empty. 33.26/9.40 We have to consider all minimal (P,Q,R)-chains. 33.26/9.40 ---------------------------------------- 33.26/9.40 33.26/9.40 (5) QDPOrderProof (EQUIVALENT) 33.26/9.40 We use the reduction pair processor [LPAR04,JAR06]. 33.26/9.40 33.26/9.40 33.26/9.40 The following pairs can be oriented strictly and are deleted. 33.26/9.40 33.26/9.40 A(a(x1)) -> B(a(x1)) 33.26/9.40 The remaining pairs can at least be oriented weakly. 33.26/9.40 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 33.26/9.40 33.26/9.40 <<< 33.26/9.40 POL(A(x_1)) = [[0A]] + [[0A, -I, 0A]] * x_1 33.26/9.40 >>> 33.26/9.40 33.26/9.40 <<< 33.26/9.40 POL(a(x_1)) = [[-I], [-I], [0A]] + [[0A, -I, 0A], [0A, -I, 0A], [1A, 0A, 1A]] * x_1 33.26/9.40 >>> 33.26/9.40 33.26/9.40 <<< 33.26/9.40 POL(B(x_1)) = [[-I]] + [[0A, 0A, -I]] * x_1 33.26/9.40 >>> 33.26/9.40 33.26/9.40 <<< 33.26/9.40 POL(b(x_1)) = [[0A], [0A], [0A]] + [[0A, 0A, 0A], [0A, 1A, 0A], [0A, 0A, -I]] * x_1 33.26/9.40 >>> popout

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all output return to SRS_Standard 2019-03-29 03.29