details

property	value
status	complete
benchmark	size-12-alpha-3-num-479.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n159.star.cs.uiowa.edu
space	Waldmann_07_size12

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	6.33437 seconds
cpu usage	21.5025
user time	20.7627
system time	0.739867
max virtual memory	1.17088648E8
max residence set size	2119104.0

stage attributes

key	value
starexec-result	YES

output

20.83/6.14 YES 20.83/6.16 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 20.83/6.16 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 20.83/6.16 20.83/6.16 20.83/6.16 Termination w.r.t. Q of the given QTRS could be proven: 20.83/6.16 20.83/6.16 (0) QTRS 20.83/6.16 (1) QTRS Reverse [EQUIVALENT, 0 ms] 20.83/6.16 (2) QTRS 20.83/6.16 (3) DependencyPairsProof [EQUIVALENT, 0 ms] 20.83/6.16 (4) QDP 20.83/6.16 (5) DependencyGraphProof [EQUIVALENT, 1 ms] 20.83/6.16 (6) QDP 20.83/6.16 (7) QDPOrderProof [EQUIVALENT, 115 ms] 20.83/6.16 (8) QDP 20.83/6.16 (9) QDPOrderProof [EQUIVALENT, 77 ms] 20.83/6.16 (10) QDP 20.83/6.16 (11) DependencyGraphProof [EQUIVALENT, 0 ms] 20.83/6.16 (12) TRUE 20.83/6.16 20.83/6.16 20.83/6.16 ---------------------------------------- 20.83/6.16 20.83/6.16 (0) 20.83/6.16 Obligation: 20.83/6.16 Q restricted rewrite system: 20.83/6.16 The TRS R consists of the following rules: 20.83/6.16 20.83/6.16 a(a(x1)) -> a(b(b(c(x1)))) 20.83/6.16 b(c(x1)) -> x1 20.83/6.16 c(b(x1)) -> a(c(x1)) 20.83/6.16 20.83/6.16 Q is empty. 20.83/6.16 20.83/6.16 ---------------------------------------- 20.83/6.16 20.83/6.16 (1) QTRS Reverse (EQUIVALENT) 20.83/6.16 We applied the QTRS Reverse Processor [REVERSE]. 20.83/6.16 ---------------------------------------- 20.83/6.16 20.83/6.16 (2) 20.83/6.16 Obligation: 20.83/6.16 Q restricted rewrite system: 20.83/6.16 The TRS R consists of the following rules: 20.83/6.16 20.83/6.16 a(a(x1)) -> c(b(b(a(x1)))) 20.83/6.16 c(b(x1)) -> x1 20.83/6.16 b(c(x1)) -> c(a(x1)) 20.83/6.16 20.83/6.16 Q is empty. 20.83/6.16 20.83/6.16 ---------------------------------------- 20.83/6.16 20.83/6.16 (3) DependencyPairsProof (EQUIVALENT) 20.83/6.16 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 20.83/6.16 ---------------------------------------- 20.83/6.16 20.83/6.16 (4) 20.83/6.16 Obligation: 20.83/6.16 Q DP problem: 20.83/6.16 The TRS P consists of the following rules: 20.83/6.16 20.83/6.16 A(a(x1)) -> C(b(b(a(x1)))) 20.83/6.16 A(a(x1)) -> B(b(a(x1))) 20.83/6.16 A(a(x1)) -> B(a(x1)) 20.83/6.16 B(c(x1)) -> C(a(x1)) 20.83/6.16 B(c(x1)) -> A(x1) 20.83/6.16 20.83/6.16 The TRS R consists of the following rules: 20.83/6.16 20.83/6.16 a(a(x1)) -> c(b(b(a(x1)))) 20.83/6.16 c(b(x1)) -> x1 20.83/6.16 b(c(x1)) -> c(a(x1)) 20.83/6.16 20.83/6.16 Q is empty. 20.83/6.16 We have to consider all minimal (P,Q,R)-chains. 20.83/6.16 ---------------------------------------- 20.83/6.16 20.83/6.16 (5) DependencyGraphProof (EQUIVALENT) 20.83/6.16 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. 20.83/6.16 ---------------------------------------- 20.83/6.16 20.83/6.16 (6) 20.83/6.16 Obligation: 20.83/6.16 Q DP problem: 20.83/6.16 The TRS P consists of the following rules: 20.83/6.16 20.83/6.16 A(a(x1)) -> B(b(a(x1))) 20.83/6.16 B(c(x1)) -> A(x1) 20.83/6.16 A(a(x1)) -> B(a(x1)) 20.83/6.16 20.83/6.16 The TRS R consists of the following rules: 20.83/6.16 20.83/6.16 a(a(x1)) -> c(b(b(a(x1)))) 20.83/6.16 c(b(x1)) -> x1 20.83/6.16 b(c(x1)) -> c(a(x1)) 20.83/6.16 20.83/6.16 Q is empty. 20.83/6.16 We have to consider all minimal (P,Q,R)-chains. popout

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