details

property	value
status	complete
benchmark	size-12-alpha-3-num-359.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n038.star.cs.uiowa.edu
space	Waldmann_07_size12

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	9.17792 seconds
cpu usage	31.5488
user time	30.1859
system time	1.3629
max virtual memory	4.1041356E7
max residence set size	3545688.0

stage attributes

key	value
starexec-result	YES

output

28.85/8.26 YES 31.38/9.04 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 31.38/9.04 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 31.38/9.04 31.38/9.04 31.38/9.04 Termination w.r.t. Q of the given QTRS could be proven: 31.38/9.04 31.38/9.04 (0) QTRS 31.38/9.04 (1) QTRS Reverse [EQUIVALENT, 0 ms] 31.38/9.04 (2) QTRS 31.38/9.04 (3) DependencyPairsProof [EQUIVALENT, 0 ms] 31.38/9.04 (4) QDP 31.38/9.04 (5) QDPOrderProof [EQUIVALENT, 187 ms] 31.38/9.04 (6) QDP 31.38/9.04 (7) QDPOrderProof [EQUIVALENT, 0 ms] 31.38/9.04 (8) QDP 31.38/9.04 (9) DependencyGraphProof [EQUIVALENT, 0 ms] 31.38/9.04 (10) TRUE 31.38/9.04 31.38/9.04 31.38/9.04 ---------------------------------------- 31.38/9.04 31.38/9.04 (0) 31.38/9.04 Obligation: 31.38/9.04 Q restricted rewrite system: 31.38/9.04 The TRS R consists of the following rules: 31.38/9.04 31.38/9.04 a(x1) -> b(x1) 31.38/9.04 a(b(b(x1))) -> c(x1) 31.38/9.04 a(c(x1)) -> c(b(a(a(x1)))) 31.38/9.04 31.38/9.04 Q is empty. 31.38/9.04 31.38/9.04 ---------------------------------------- 31.38/9.04 31.38/9.04 (1) QTRS Reverse (EQUIVALENT) 31.38/9.04 We applied the QTRS Reverse Processor [REVERSE]. 31.38/9.04 ---------------------------------------- 31.38/9.04 31.38/9.04 (2) 31.38/9.04 Obligation: 31.38/9.04 Q restricted rewrite system: 31.38/9.04 The TRS R consists of the following rules: 31.38/9.04 31.38/9.04 a(x1) -> b(x1) 31.38/9.04 b(b(a(x1))) -> c(x1) 31.38/9.04 c(a(x1)) -> a(a(b(c(x1)))) 31.38/9.04 31.38/9.04 Q is empty. 31.38/9.04 31.38/9.04 ---------------------------------------- 31.38/9.04 31.38/9.04 (3) DependencyPairsProof (EQUIVALENT) 31.38/9.04 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 31.38/9.04 ---------------------------------------- 31.38/9.04 31.38/9.04 (4) 31.38/9.04 Obligation: 31.38/9.04 Q DP problem: 31.38/9.04 The TRS P consists of the following rules: 31.38/9.04 31.38/9.04 A(x1) -> B(x1) 31.38/9.04 B(b(a(x1))) -> C(x1) 31.38/9.04 C(a(x1)) -> A(a(b(c(x1)))) 31.38/9.04 C(a(x1)) -> A(b(c(x1))) 31.38/9.04 C(a(x1)) -> B(c(x1)) 31.38/9.04 C(a(x1)) -> C(x1) 31.38/9.04 31.38/9.04 The TRS R consists of the following rules: 31.38/9.04 31.38/9.04 a(x1) -> b(x1) 31.38/9.04 b(b(a(x1))) -> c(x1) 31.38/9.04 c(a(x1)) -> a(a(b(c(x1)))) 31.38/9.04 31.38/9.04 Q is empty. 31.38/9.04 We have to consider all minimal (P,Q,R)-chains. 31.38/9.04 ---------------------------------------- 31.38/9.04 31.38/9.04 (5) QDPOrderProof (EQUIVALENT) 31.38/9.04 We use the reduction pair processor [LPAR04,JAR06]. 31.38/9.04 31.38/9.04 31.38/9.04 The following pairs can be oriented strictly and are deleted. 31.38/9.04 31.38/9.04 C(a(x1)) -> A(b(c(x1))) 31.38/9.04 The remaining pairs can at least be oriented weakly. 31.38/9.04 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 31.38/9.04 31.38/9.04 <<< 31.38/9.04 POL(A(x_1)) = [[0A]] + [[0A, 0A, -I]] * x_1 31.38/9.04 >>> 31.38/9.04 31.38/9.04 <<< 31.38/9.04 POL(B(x_1)) = [[0A]] + [[0A, 0A, -I]] * x_1 31.38/9.04 >>> 31.38/9.04 31.38/9.04 <<< 31.38/9.04 POL(b(x_1)) = [[0A], [-I], [-I]] + [[-I, -I, 0A], [-I, -I, 0A], [-I, 0A, 0A]] * x_1 31.38/9.04 >>> 31.38/9.04 popout

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all output return to SRS_Standard 2019-03-29 03.29