details

property	value
status	complete
benchmark	size-12-alpha-3-num-9.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n082.star.cs.uiowa.edu
space	Waldmann_07_size12

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	6.07234 seconds
cpu usage	19.6602
user time	18.7856
system time	0.874617
max virtual memory	1.00258196E8
max residence set size	2960532.0

stage attributes

key	value
starexec-result	YES

output

18.63/5.83 YES 19.37/5.92 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 19.37/5.92 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 19.37/5.92 19.37/5.92 19.37/5.92 Termination w.r.t. Q of the given QTRS could be proven: 19.37/5.92 19.37/5.92 (0) QTRS 19.37/5.92 (1) QTRS Reverse [EQUIVALENT, 0 ms] 19.37/5.92 (2) QTRS 19.37/5.92 (3) DependencyPairsProof [EQUIVALENT, 1 ms] 19.37/5.92 (4) QDP 19.37/5.92 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 19.37/5.92 (6) QDP 19.37/5.92 (7) QDPOrderProof [EQUIVALENT, 86 ms] 19.37/5.92 (8) QDP 19.37/5.92 (9) PisEmptyProof [EQUIVALENT, 0 ms] 19.37/5.92 (10) YES 19.37/5.92 19.37/5.92 19.37/5.92 ---------------------------------------- 19.37/5.92 19.37/5.92 (0) 19.37/5.92 Obligation: 19.37/5.92 Q restricted rewrite system: 19.37/5.92 The TRS R consists of the following rules: 19.37/5.92 19.37/5.92 a(x1) -> x1 19.37/5.92 a(x1) -> b(x1) 19.37/5.92 a(b(c(x1))) -> c(c(a(b(a(x1))))) 19.37/5.92 b(x1) -> x1 19.37/5.92 19.37/5.92 Q is empty. 19.37/5.92 19.37/5.92 ---------------------------------------- 19.37/5.92 19.37/5.92 (1) QTRS Reverse (EQUIVALENT) 19.37/5.92 We applied the QTRS Reverse Processor [REVERSE]. 19.37/5.92 ---------------------------------------- 19.37/5.92 19.37/5.92 (2) 19.37/5.92 Obligation: 19.37/5.92 Q restricted rewrite system: 19.37/5.92 The TRS R consists of the following rules: 19.37/5.92 19.37/5.92 a(x1) -> x1 19.37/5.92 a(x1) -> b(x1) 19.37/5.92 c(b(a(x1))) -> a(b(a(c(c(x1))))) 19.37/5.92 b(x1) -> x1 19.37/5.92 19.37/5.92 Q is empty. 19.37/5.92 19.37/5.92 ---------------------------------------- 19.37/5.92 19.37/5.92 (3) DependencyPairsProof (EQUIVALENT) 19.37/5.92 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 19.37/5.92 ---------------------------------------- 19.37/5.92 19.37/5.92 (4) 19.37/5.92 Obligation: 19.37/5.92 Q DP problem: 19.37/5.92 The TRS P consists of the following rules: 19.37/5.92 19.37/5.92 A(x1) -> B(x1) 19.37/5.92 C(b(a(x1))) -> A(b(a(c(c(x1))))) 19.37/5.92 C(b(a(x1))) -> B(a(c(c(x1)))) 19.37/5.92 C(b(a(x1))) -> A(c(c(x1))) 19.37/5.92 C(b(a(x1))) -> C(c(x1)) 19.37/5.92 C(b(a(x1))) -> C(x1) 19.37/5.92 19.37/5.92 The TRS R consists of the following rules: 19.37/5.92 19.37/5.92 a(x1) -> x1 19.37/5.92 a(x1) -> b(x1) 19.37/5.92 c(b(a(x1))) -> a(b(a(c(c(x1))))) 19.37/5.92 b(x1) -> x1 19.37/5.92 19.37/5.92 Q is empty. 19.37/5.92 We have to consider all minimal (P,Q,R)-chains. 19.37/5.92 ---------------------------------------- 19.37/5.92 19.37/5.92 (5) DependencyGraphProof (EQUIVALENT) 19.37/5.92 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 4 less nodes. 19.37/5.92 ---------------------------------------- 19.37/5.92 19.37/5.92 (6) 19.37/5.92 Obligation: 19.37/5.92 Q DP problem: 19.37/5.92 The TRS P consists of the following rules: 19.37/5.92 19.37/5.92 C(b(a(x1))) -> C(x1) 19.37/5.92 C(b(a(x1))) -> C(c(x1)) 19.37/5.92 19.37/5.92 The TRS R consists of the following rules: 19.37/5.92 19.37/5.92 a(x1) -> x1 19.37/5.92 a(x1) -> b(x1) 19.37/5.92 c(b(a(x1))) -> a(b(a(c(c(x1))))) 19.37/5.92 b(x1) -> x1 19.37/5.92 popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to SRS_Standard 2019-03-29 03.29