details

property	value
status	complete
benchmark	size-12-alpha-3-num-125.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n165.star.cs.uiowa.edu
space	Waldmann_07_size12

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	9.84764 seconds
cpu usage	34.3887
user time	33.0309
system time	1.35778
max virtual memory	4.1940452E7
max residence set size	4005748.0

stage attributes

key	value
starexec-result	YES

output

33.60/9.49 YES 33.98/9.57 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 33.98/9.57 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 33.98/9.57 33.98/9.57 33.98/9.57 Termination w.r.t. Q of the given QTRS could be proven: 33.98/9.57 33.98/9.57 (0) QTRS 33.98/9.57 (1) QTRS Reverse [EQUIVALENT, 0 ms] 33.98/9.57 (2) QTRS 33.98/9.57 (3) DependencyPairsProof [EQUIVALENT, 0 ms] 33.98/9.57 (4) QDP 33.98/9.57 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 33.98/9.57 (6) QDP 33.98/9.57 (7) QDPOrderProof [EQUIVALENT, 143 ms] 33.98/9.57 (8) QDP 33.98/9.57 (9) QDPOrderProof [EQUIVALENT, 76 ms] 33.98/9.57 (10) QDP 33.98/9.57 (11) DependencyGraphProof [EQUIVALENT, 0 ms] 33.98/9.57 (12) TRUE 33.98/9.57 33.98/9.57 33.98/9.57 ---------------------------------------- 33.98/9.57 33.98/9.57 (0) 33.98/9.57 Obligation: 33.98/9.57 Q restricted rewrite system: 33.98/9.57 The TRS R consists of the following rules: 33.98/9.57 33.98/9.57 a(x1) -> x1 33.98/9.57 a(a(b(x1))) -> c(c(a(c(x1)))) 33.98/9.57 c(c(x1)) -> b(a(x1)) 33.98/9.57 33.98/9.57 Q is empty. 33.98/9.57 33.98/9.57 ---------------------------------------- 33.98/9.57 33.98/9.57 (1) QTRS Reverse (EQUIVALENT) 33.98/9.57 We applied the QTRS Reverse Processor [REVERSE]. 33.98/9.57 ---------------------------------------- 33.98/9.57 33.98/9.57 (2) 33.98/9.57 Obligation: 33.98/9.57 Q restricted rewrite system: 33.98/9.57 The TRS R consists of the following rules: 33.98/9.57 33.98/9.57 a(x1) -> x1 33.98/9.57 b(a(a(x1))) -> c(a(c(c(x1)))) 33.98/9.58 c(c(x1)) -> a(b(x1)) 33.98/9.58 33.98/9.58 Q is empty. 33.98/9.58 33.98/9.58 ---------------------------------------- 33.98/9.58 33.98/9.58 (3) DependencyPairsProof (EQUIVALENT) 33.98/9.58 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 33.98/9.58 ---------------------------------------- 33.98/9.58 33.98/9.58 (4) 33.98/9.58 Obligation: 33.98/9.58 Q DP problem: 33.98/9.58 The TRS P consists of the following rules: 33.98/9.58 33.98/9.58 B(a(a(x1))) -> C(a(c(c(x1)))) 33.98/9.58 B(a(a(x1))) -> A(c(c(x1))) 33.98/9.58 B(a(a(x1))) -> C(c(x1)) 33.98/9.58 B(a(a(x1))) -> C(x1) 33.98/9.58 C(c(x1)) -> A(b(x1)) 33.98/9.58 C(c(x1)) -> B(x1) 33.98/9.58 33.98/9.58 The TRS R consists of the following rules: 33.98/9.58 33.98/9.58 a(x1) -> x1 33.98/9.58 b(a(a(x1))) -> c(a(c(c(x1)))) 33.98/9.58 c(c(x1)) -> a(b(x1)) 33.98/9.58 33.98/9.58 Q is empty. 33.98/9.58 We have to consider all minimal (P,Q,R)-chains. 33.98/9.58 ---------------------------------------- 33.98/9.58 33.98/9.58 (5) DependencyGraphProof (EQUIVALENT) 33.98/9.58 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. 33.98/9.58 ---------------------------------------- 33.98/9.58 33.98/9.58 (6) 33.98/9.58 Obligation: 33.98/9.58 Q DP problem: 33.98/9.58 The TRS P consists of the following rules: 33.98/9.58 33.98/9.58 C(c(x1)) -> B(x1) 33.98/9.58 B(a(a(x1))) -> C(a(c(c(x1)))) 33.98/9.58 B(a(a(x1))) -> C(c(x1)) 33.98/9.58 B(a(a(x1))) -> C(x1) 33.98/9.58 33.98/9.58 The TRS R consists of the following rules: 33.98/9.58 33.98/9.58 a(x1) -> x1 33.98/9.58 b(a(a(x1))) -> c(a(c(c(x1)))) 33.98/9.58 c(c(x1)) -> a(b(x1)) 33.98/9.58 popout

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all output return to SRS_Standard 2019-03-29 03.29