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SRS_Standard 2019-03-29 03.29 pair #432291619
details
property
value
status
complete
benchmark
size-11-alpha-3-num-16.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n012.star.cs.uiowa.edu
space
Waldmann_07_size11
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
3.13515 seconds
cpu usage
9.18655
user time
8.68609
system time
0.500463
max virtual memory
1.980776E7
max residence set size
1393344.0
stage attributes
key
value
starexec-result
YES
output
8.53/2.98 YES 9.08/3.08 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 9.08/3.08 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 9.08/3.08 9.08/3.08 9.08/3.08 Termination w.r.t. Q of the given QTRS could be proven: 9.08/3.08 9.08/3.08 (0) QTRS 9.08/3.08 (1) QTRS Reverse [EQUIVALENT, 0 ms] 9.08/3.08 (2) QTRS 9.08/3.08 (3) DependencyPairsProof [EQUIVALENT, 1 ms] 9.08/3.08 (4) QDP 9.08/3.08 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 9.08/3.08 (6) QDP 9.08/3.08 (7) QDPSizeChangeProof [EQUIVALENT, 2 ms] 9.08/3.08 (8) YES 9.08/3.08 9.08/3.08 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (0) 9.08/3.08 Obligation: 9.08/3.08 Q restricted rewrite system: 9.08/3.08 The TRS R consists of the following rules: 9.08/3.08 9.08/3.08 a(x1) -> x1 9.08/3.08 a(a(x1)) -> a(b(c(x1))) 9.08/3.08 c(b(x1)) -> a(c(a(x1))) 9.08/3.08 9.08/3.08 Q is empty. 9.08/3.08 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (1) QTRS Reverse (EQUIVALENT) 9.08/3.08 We applied the QTRS Reverse Processor [REVERSE]. 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (2) 9.08/3.08 Obligation: 9.08/3.08 Q restricted rewrite system: 9.08/3.08 The TRS R consists of the following rules: 9.08/3.08 9.08/3.08 a(x1) -> x1 9.08/3.08 a(a(x1)) -> c(b(a(x1))) 9.08/3.08 b(c(x1)) -> a(c(a(x1))) 9.08/3.08 9.08/3.08 Q is empty. 9.08/3.08 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (3) DependencyPairsProof (EQUIVALENT) 9.08/3.08 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (4) 9.08/3.08 Obligation: 9.08/3.08 Q DP problem: 9.08/3.08 The TRS P consists of the following rules: 9.08/3.08 9.08/3.08 A(a(x1)) -> B(a(x1)) 9.08/3.08 B(c(x1)) -> A(c(a(x1))) 9.08/3.08 B(c(x1)) -> A(x1) 9.08/3.08 9.08/3.08 The TRS R consists of the following rules: 9.08/3.08 9.08/3.08 a(x1) -> x1 9.08/3.08 a(a(x1)) -> c(b(a(x1))) 9.08/3.08 b(c(x1)) -> a(c(a(x1))) 9.08/3.08 9.08/3.08 Q is empty. 9.08/3.08 We have to consider all minimal (P,Q,R)-chains. 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (5) DependencyGraphProof (EQUIVALENT) 9.08/3.08 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (6) 9.08/3.08 Obligation: 9.08/3.08 Q DP problem: 9.08/3.08 The TRS P consists of the following rules: 9.08/3.08 9.08/3.08 B(c(x1)) -> A(x1) 9.08/3.08 A(a(x1)) -> B(a(x1)) 9.08/3.08 9.08/3.08 The TRS R consists of the following rules: 9.08/3.08 9.08/3.08 a(x1) -> x1 9.08/3.08 a(a(x1)) -> c(b(a(x1))) 9.08/3.08 b(c(x1)) -> a(c(a(x1))) 9.08/3.08 9.08/3.08 Q is empty. 9.08/3.08 We have to consider all minimal (P,Q,R)-chains. 9.08/3.08 ---------------------------------------- 9.08/3.08 9.08/3.08 (7) QDPSizeChangeProof (EQUIVALENT) 9.08/3.08 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 9.08/3.08 9.08/3.08 From the DPs we obtained the following set of size-change graphs: 9.08/3.08 *A(a(x1)) -> B(a(x1))
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