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SRS_Standard 2019-03-29 03.29 pair #432291649
details
property
value
status
complete
benchmark
size-11-alpha-3-num-10.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n168.star.cs.uiowa.edu
space
Waldmann_07_size11
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
4.84963 seconds
cpu usage
15.6173
user time
14.8945
system time
0.722864
max virtual memory
9.8591196E7
max residence set size
1855904.0
stage attributes
key
value
starexec-result
YES
output
14.27/4.51 YES 15.18/4.71 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 15.18/4.71 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 15.18/4.71 15.18/4.71 15.18/4.71 Termination w.r.t. Q of the given QTRS could be proven: 15.18/4.71 15.18/4.71 (0) QTRS 15.18/4.71 (1) QTRS Reverse [EQUIVALENT, 0 ms] 15.18/4.71 (2) QTRS 15.18/4.71 (3) DependencyPairsProof [EQUIVALENT, 2 ms] 15.18/4.71 (4) QDP 15.18/4.71 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 15.18/4.71 (6) QDP 15.18/4.71 (7) QDPOrderProof [EQUIVALENT, 112 ms] 15.18/4.71 (8) QDP 15.18/4.71 (9) PisEmptyProof [EQUIVALENT, 0 ms] 15.18/4.71 (10) YES 15.18/4.71 15.18/4.71 15.18/4.71 ---------------------------------------- 15.18/4.71 15.18/4.71 (0) 15.18/4.71 Obligation: 15.18/4.71 Q restricted rewrite system: 15.18/4.71 The TRS R consists of the following rules: 15.18/4.71 15.18/4.71 a(x1) -> x1 15.18/4.71 a(a(b(x1))) -> b(b(a(a(x1)))) 15.18/4.71 b(x1) -> c(a(x1)) 15.18/4.71 15.18/4.71 Q is empty. 15.18/4.71 15.18/4.71 ---------------------------------------- 15.18/4.71 15.18/4.71 (1) QTRS Reverse (EQUIVALENT) 15.18/4.71 We applied the QTRS Reverse Processor [REVERSE]. 15.18/4.71 ---------------------------------------- 15.18/4.71 15.18/4.71 (2) 15.18/4.71 Obligation: 15.18/4.71 Q restricted rewrite system: 15.18/4.71 The TRS R consists of the following rules: 15.18/4.71 15.18/4.71 a(x1) -> x1 15.18/4.71 b(a(a(x1))) -> a(a(b(b(x1)))) 15.18/4.71 b(x1) -> a(c(x1)) 15.18/4.71 15.18/4.71 Q is empty. 15.18/4.71 15.18/4.71 ---------------------------------------- 15.18/4.72 15.18/4.72 (3) DependencyPairsProof (EQUIVALENT) 15.18/4.72 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 15.18/4.72 ---------------------------------------- 15.18/4.72 15.18/4.72 (4) 15.18/4.72 Obligation: 15.18/4.72 Q DP problem: 15.18/4.72 The TRS P consists of the following rules: 15.18/4.72 15.18/4.72 B(a(a(x1))) -> A(a(b(b(x1)))) 15.18/4.72 B(a(a(x1))) -> A(b(b(x1))) 15.18/4.72 B(a(a(x1))) -> B(b(x1)) 15.18/4.72 B(a(a(x1))) -> B(x1) 15.18/4.72 B(x1) -> A(c(x1)) 15.18/4.72 15.18/4.72 The TRS R consists of the following rules: 15.18/4.72 15.18/4.72 a(x1) -> x1 15.18/4.72 b(a(a(x1))) -> a(a(b(b(x1)))) 15.18/4.72 b(x1) -> a(c(x1)) 15.18/4.72 15.18/4.72 Q is empty. 15.18/4.72 We have to consider all minimal (P,Q,R)-chains. 15.18/4.72 ---------------------------------------- 15.18/4.72 15.18/4.72 (5) DependencyGraphProof (EQUIVALENT) 15.18/4.72 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 3 less nodes. 15.18/4.72 ---------------------------------------- 15.18/4.72 15.18/4.72 (6) 15.18/4.72 Obligation: 15.18/4.72 Q DP problem: 15.18/4.72 The TRS P consists of the following rules: 15.18/4.72 15.18/4.72 B(a(a(x1))) -> B(x1) 15.18/4.72 B(a(a(x1))) -> B(b(x1)) 15.18/4.72 15.18/4.72 The TRS R consists of the following rules: 15.18/4.72 15.18/4.72 a(x1) -> x1 15.18/4.72 b(a(a(x1))) -> a(a(b(b(x1)))) 15.18/4.72 b(x1) -> a(c(x1)) 15.18/4.72 15.18/4.72 Q is empty. 15.18/4.72 We have to consider all minimal (P,Q,R)-chains. 15.18/4.72 ---------------------------------------- 15.18/4.72 15.18/4.72 (7) QDPOrderProof (EQUIVALENT)
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