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SRS_Standard 2019-03-29 03.29 pair #432291690
details
property
value
status
complete
benchmark
z106.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n128.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
1.74978 seconds
cpu usage
5.6568
user time
4.23656
system time
1.42024
max virtual memory
3504104.0
max residence set size
66456.0
stage attributes
key
value
starexec-result
YES
output
4.82/1.74 YES 4.82/1.74 4.82/1.74 Problem: 4.82/1.74 a(a(x1)) -> b(b(b(x1))) 4.82/1.74 b(x1) -> c(c(d(x1))) 4.82/1.74 c(x1) -> d(d(d(x1))) 4.82/1.74 b(c(x1)) -> c(b(x1)) 4.82/1.74 b(c(d(x1))) -> a(x1) 4.82/1.74 4.82/1.74 Proof: 4.82/1.74 String Reversal Processor: 4.82/1.74 a(a(x1)) -> b(b(b(x1))) 4.82/1.74 b(x1) -> d(c(c(x1))) 4.82/1.74 c(x1) -> d(d(d(x1))) 4.82/1.74 c(b(x1)) -> b(c(x1)) 4.82/1.74 d(c(b(x1))) -> a(x1) 4.82/1.74 Matrix Interpretation Processor: dim=1 4.82/1.74 4.82/1.74 interpretation: 4.82/1.74 [c](x0) = x0 + 4, 4.82/1.74 4.82/1.74 [d](x0) = x0, 4.82/1.74 4.82/1.74 [b](x0) = x0 + 8, 4.82/1.74 4.82/1.74 [a](x0) = x0 + 12 4.82/1.74 orientation: 4.82/1.74 a(a(x1)) = x1 + 24 >= x1 + 24 = b(b(b(x1))) 4.82/1.74 4.82/1.74 b(x1) = x1 + 8 >= x1 + 8 = d(c(c(x1))) 4.82/1.74 4.82/1.74 c(x1) = x1 + 4 >= x1 = d(d(d(x1))) 4.82/1.74 4.82/1.74 c(b(x1)) = x1 + 12 >= x1 + 12 = b(c(x1)) 4.82/1.74 4.82/1.74 d(c(b(x1))) = x1 + 12 >= x1 + 12 = a(x1) 4.82/1.74 problem: 4.82/1.74 a(a(x1)) -> b(b(b(x1))) 4.82/1.74 b(x1) -> d(c(c(x1))) 4.82/1.74 c(b(x1)) -> b(c(x1)) 4.82/1.74 d(c(b(x1))) -> a(x1) 4.82/1.74 Matrix Interpretation Processor: dim=1 4.82/1.74 4.82/1.74 interpretation: 4.82/1.74 [c](x0) = x0, 4.82/1.74 4.82/1.74 [d](x0) = x0 + 1, 4.82/1.74 4.82/1.74 [b](x0) = x0 + 1, 4.82/1.74 4.82/1.74 [a](x0) = x0 + 2 4.82/1.74 orientation: 4.82/1.74 a(a(x1)) = x1 + 4 >= x1 + 3 = b(b(b(x1))) 4.82/1.75 4.82/1.75 b(x1) = x1 + 1 >= x1 + 1 = d(c(c(x1))) 4.82/1.75 4.82/1.75 c(b(x1)) = x1 + 1 >= x1 + 1 = b(c(x1)) 4.82/1.75 4.82/1.75 d(c(b(x1))) = x1 + 2 >= x1 + 2 = a(x1) 4.82/1.75 problem: 4.82/1.75 b(x1) -> d(c(c(x1))) 4.82/1.75 c(b(x1)) -> b(c(x1)) 4.82/1.75 d(c(b(x1))) -> a(x1) 4.82/1.75 KBO Processor: 4.82/1.75 weight function: 4.82/1.75 w0 = 1 4.82/1.75 w(d) = w(b) = w(a) = 1 4.82/1.75 w(c) = 0 4.82/1.75 precedence: 4.82/1.75 c > b > d ~ a 4.82/1.75 problem: 4.82/1.75 4.82/1.75 Qed 4.82/1.75 EOF
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