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SRS_Standard 2019-03-29 03.29 pair #432291726
details
property
value
status
complete
benchmark
z111.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n164.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
5.16615 seconds
cpu usage
18.9517
user time
16.3864
system time
2.56525
max virtual memory
3575988.0
max residence set size
79756.0
stage attributes
key
value
starexec-result
YES
output
18.51/5.15 YES 18.51/5.16 18.51/5.16 Problem: 18.51/5.16 a(a(x1)) -> b(c(c(c(x1)))) 18.51/5.16 b(c(x1)) -> d(d(d(d(x1)))) 18.51/5.16 a(x1) -> d(c(d(x1))) 18.51/5.16 b(b(x1)) -> c(c(c(x1))) 18.51/5.16 c(c(x1)) -> d(d(d(x1))) 18.51/5.16 c(d(d(x1))) -> a(x1) 18.51/5.16 18.51/5.16 Proof: 18.51/5.16 Matrix Interpretation Processor: dim=1 18.51/5.16 18.51/5.16 interpretation: 18.51/5.16 [d](x0) = x0 + 4, 18.51/5.16 18.51/5.16 [b](x0) = x0 + 10, 18.51/5.16 18.51/5.16 [c](x0) = x0 + 6, 18.51/5.16 18.51/5.16 [a](x0) = x0 + 14 18.51/5.16 orientation: 18.51/5.16 a(a(x1)) = x1 + 28 >= x1 + 28 = b(c(c(c(x1)))) 18.51/5.16 18.51/5.16 b(c(x1)) = x1 + 16 >= x1 + 16 = d(d(d(d(x1)))) 18.51/5.16 18.51/5.16 a(x1) = x1 + 14 >= x1 + 14 = d(c(d(x1))) 18.51/5.16 18.51/5.16 b(b(x1)) = x1 + 20 >= x1 + 18 = c(c(c(x1))) 18.51/5.16 18.51/5.16 c(c(x1)) = x1 + 12 >= x1 + 12 = d(d(d(x1))) 18.51/5.16 18.51/5.16 c(d(d(x1))) = x1 + 14 >= x1 + 14 = a(x1) 18.51/5.16 problem: 18.51/5.16 a(a(x1)) -> b(c(c(c(x1)))) 18.51/5.16 b(c(x1)) -> d(d(d(d(x1)))) 18.51/5.16 a(x1) -> d(c(d(x1))) 18.51/5.16 c(c(x1)) -> d(d(d(x1))) 18.51/5.16 c(d(d(x1))) -> a(x1) 18.51/5.16 Matrix Interpretation Processor: dim=1 18.51/5.16 18.51/5.16 interpretation: 18.51/5.16 [d](x0) = x0 + 2, 18.51/5.16 18.51/5.16 [b](x0) = x0, 18.51/5.16 18.51/5.16 [c](x0) = x0 + 8, 18.51/5.16 18.51/5.16 [a](x0) = x0 + 12 18.51/5.16 orientation: 18.51/5.16 a(a(x1)) = x1 + 24 >= x1 + 24 = b(c(c(c(x1)))) 18.51/5.16 18.51/5.16 b(c(x1)) = x1 + 8 >= x1 + 8 = d(d(d(d(x1)))) 18.51/5.16 18.51/5.16 a(x1) = x1 + 12 >= x1 + 12 = d(c(d(x1))) 18.51/5.16 18.51/5.16 c(c(x1)) = x1 + 16 >= x1 + 6 = d(d(d(x1))) 18.51/5.16 18.51/5.16 c(d(d(x1))) = x1 + 12 >= x1 + 12 = a(x1) 18.51/5.16 problem: 18.51/5.16 a(a(x1)) -> b(c(c(c(x1)))) 18.51/5.16 b(c(x1)) -> d(d(d(d(x1)))) 18.51/5.16 a(x1) -> d(c(d(x1))) 18.51/5.16 c(d(d(x1))) -> a(x1) 18.51/5.16 String Reversal Processor: 18.51/5.16 a(a(x1)) -> c(c(c(b(x1)))) 18.51/5.16 c(b(x1)) -> d(d(d(d(x1)))) 18.51/5.16 a(x1) -> d(c(d(x1))) 18.51/5.16 d(d(c(x1))) -> a(x1) 18.51/5.16 Matrix Interpretation Processor: dim=3 18.51/5.16 18.51/5.16 interpretation: 18.51/5.16 [1 0 1] 18.51/5.16 [d](x0) = [0 0 0]x0 18.51/5.16 [1 0 0] , 18.51/5.16 18.51/5.16 [3 0 1] [3] 18.51/5.16 [b](x0) = [2 0 2]x0 + [0] 18.51/5.16 [3 1 2] [1], 18.51/5.16 18.51/5.16 [1 1 0] [1] 18.51/5.16 [c](x0) = [0 0 0]x0 + [0] 18.51/5.16 [0 0 1] [0], 18.51/5.16 18.51/5.16 [2 0 1] [2] 18.51/5.16 [a](x0) = [0 0 0]x0 + [0] 18.51/5.16 [1 1 1] [1] 18.51/5.16 orientation: 18.51/5.16 [5 1 3] [7] [5 0 3] [6] 18.51/5.16 a(a(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = c(c(c(b(x1)))) 18.51/5.16 [3 1 2] [4] [3 1 2] [1] 18.51/5.16 18.51/5.16 [5 0 3] [4] [5 0 3] 18.51/5.16 c(b(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 = d(d(d(d(x1)))) 18.51/5.16 [3 1 2] [1] [3 0 2] 18.51/5.16 18.51/5.16 [2 0 1] [2] [2 0 1] [1] 18.51/5.16 a(x1) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = d(c(d(x1))) 18.51/5.16 [1 1 1] [1] [1 0 1] [1] 18.51/5.16
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