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SRS_Standard 2019-03-29 03.29 pair #432292002
details
property
value
status
complete
benchmark
z103.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n164.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
0.895501 seconds
cpu usage
2.3388
user time
1.63386
system time
0.704948
max virtual memory
2891680.0
max residence set size
61988.0
stage attributes
key
value
starexec-result
YES
output
2.30/0.88 YES 2.30/0.89 2.30/0.89 Problem: 2.30/0.89 a(d(x1)) -> d(b(x1)) 2.30/0.89 a(x1) -> b(b(b(x1))) 2.30/0.89 b(d(b(x1))) -> a(c(x1)) 2.30/0.89 c(x1) -> d(x1) 2.30/0.89 2.30/0.89 Proof: 2.30/0.89 Matrix Interpretation Processor: dim=1 2.30/0.89 2.30/0.89 interpretation: 2.30/0.89 [c](x0) = 4x0, 2.30/0.89 2.30/0.89 [b](x0) = x0 + 1, 2.30/0.89 2.30/0.89 [a](x0) = x0 + 4, 2.30/0.89 2.30/0.89 [d](x0) = 4x0 2.30/0.89 orientation: 2.30/0.89 a(d(x1)) = 4x1 + 4 >= 4x1 + 4 = d(b(x1)) 2.30/0.89 2.30/0.89 a(x1) = x1 + 4 >= x1 + 3 = b(b(b(x1))) 2.30/0.89 2.30/0.89 b(d(b(x1))) = 4x1 + 5 >= 4x1 + 4 = a(c(x1)) 2.30/0.89 2.30/0.89 c(x1) = 4x1 >= 4x1 = d(x1) 2.30/0.89 problem: 2.30/0.89 a(d(x1)) -> d(b(x1)) 2.30/0.89 c(x1) -> d(x1) 2.30/0.89 String Reversal Processor: 2.30/0.89 d(a(x1)) -> b(d(x1)) 2.30/0.89 c(x1) -> d(x1) 2.30/0.89 KBO Processor: 2.30/0.89 weight function: 2.30/0.89 w0 = 1 2.30/0.89 w(c) = w(b) = w(a) = w(d) = 1 2.30/0.89 precedence: 2.30/0.89 a > c > d > b 2.30/0.89 problem: 2.30/0.89 2.30/0.89 Qed 2.30/0.89 EOF
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