SRS_Standard 2019-03-29 03.29 pair #432292092

details

property	value
status	complete
benchmark	z015.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n041.star.cs.uiowa.edu
space	Zantema_04

run statistics

property	value
solver	ttt2-1.19
configuration	ttt2
runtime (wallclock)	1.45228 seconds
cpu usage	4.45574
user time	3.23382
system time	1.22192
max virtual memory	3475872.0
max residence set size	63344.0

stage attributes

key	value
starexec-result	YES

output

3.97/1.44	YES
3.97/1.57	
3.97/1.57	Problem:
3.97/1.57	 a(b(x1)) -> b(a(a(a(x1))))
3.97/1.57	 b(a(x1)) -> a(a(x1))
3.97/1.57	 a(a(x1)) -> a(c(b(x1)))
3.97/1.57	
3.97/1.57	Proof:
3.97/1.57	 Matrix Interpretation Processor: dim=2
3.97/1.57	  
3.97/1.57	  interpretation:
3.97/1.57	             [1 0]  
3.97/1.57	   [c](x0) = [0 0]x0,
3.97/1.57	   
3.97/1.57	             [1 1]  
3.97/1.57	   [a](x0) = [0 1]x0,
3.97/1.57	   
3.97/1.57	             [1 1]     [0]
3.97/1.57	   [b](x0) = [0 3]x0 + [3]
3.97/1.57	  orientation:
3.97/1.57	              [1 4]     [3]    [1 4]     [0]                 
3.97/1.57	   a(b(x1)) = [0 3]x1 + [3] >= [0 3]x1 + [3] = b(a(a(a(x1))))
3.97/1.57	   
3.97/1.57	              [1 2]     [0]    [1 2]             
3.97/1.57	   b(a(x1)) = [0 3]x1 + [3] >= [0 1]x1 = a(a(x1))
3.97/1.57	   
3.97/1.57	              [1 2]      [1 1]                
3.97/1.57	   a(a(x1)) = [0 1]x1 >= [0 0]x1 = a(c(b(x1)))
3.97/1.57	  problem:
3.97/1.57	   b(a(x1)) -> a(a(x1))
3.97/1.57	   a(a(x1)) -> a(c(b(x1)))
3.97/1.57	  String Reversal Processor:
3.97/1.57	   a(b(x1)) -> a(a(x1))
3.97/1.57	   a(a(x1)) -> b(c(a(x1)))
3.97/1.57	   Matrix Interpretation Processor: dim=3
3.97/1.57	    
3.97/1.57	    interpretation:
3.97/1.57	               [1 0 0]  
3.97/1.57	     [c](x0) = [0 1 1]x0
3.97/1.57	               [0 0 0]  ,
3.97/1.57	     
3.97/1.57	               [1 0 1]     [1]
3.97/1.57	     [a](x0) = [1 1 1]x0 + [0]
3.97/1.57	               [1 1 1]     [1],
3.97/1.58	     
3.97/1.58	               [1 0 1]     [1]
3.97/1.58	     [b](x0) = [1 1 1]x0 + [0]
3.97/1.58	               [1 1 1]     [1]
3.97/1.58	    orientation:
3.97/1.58	                [2 1 2]     [3]    [2 1 2]     [3]           
3.97/1.58	     a(b(x1)) = [3 2 3]x1 + [2] >= [3 2 3]x1 + [2] = a(a(x1))
3.97/1.58	                [3 2 3]     [3]    [3 2 3]     [3]           
3.97/1.58	     
3.97/1.58	                [2 1 2]     [3]    [1 0 1]     [2]              
3.97/1.58	     a(a(x1)) = [3 2 3]x1 + [2] >= [3 2 3]x1 + [2] = b(c(a(x1)))
3.97/1.58	                [3 2 3]     [3]    [3 2 3]     [3]              
3.97/1.58	    problem:
3.97/1.58	     a(b(x1)) -> a(a(x1))
3.97/1.58	    String Reversal Processor:
3.97/1.58	     b(a(x1)) -> a(a(x1))
3.97/1.58	     KBO Processor:
3.97/1.58	      weight function:
3.97/1.58	       w0 = 1
3.97/1.58	       w(a) = w(b) = 1
3.97/1.58	      precedence:
3.97/1.58	       b > a
3.97/1.58	      problem:
3.97/1.58	       
3.97/1.58	      Qed
3.97/1.58	EOF

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