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SRS_Standard 2019-03-29 03.29 pair #432292176
details
property
value
status
complete
benchmark
z112.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n143.star.cs.uiowa.edu
space
Zantema_04
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
1.94184 seconds
cpu usage
6.36299
user time
4.78265
system time
1.58033
max virtual memory
3568440.0
max residence set size
68672.0
stage attributes
key
value
starexec-result
YES
output
5.63/1.93 YES 5.63/1.93 5.63/1.93 Problem: 5.63/1.93 a(a(x1)) -> b(c(x1)) 5.63/1.93 b(b(x1)) -> c(d(x1)) 5.63/1.93 b(x1) -> a(x1) 5.63/1.93 c(c(x1)) -> d(f(x1)) 5.63/1.93 d(d(x1)) -> f(f(f(x1))) 5.63/1.93 d(x1) -> b(x1) 5.63/1.93 f(f(x1)) -> g(a(x1)) 5.63/1.93 g(g(x1)) -> a(x1) 5.63/1.93 5.63/1.93 Proof: 5.63/1.93 String Reversal Processor: 5.63/1.93 a(a(x1)) -> c(b(x1)) 5.63/1.93 b(b(x1)) -> d(c(x1)) 5.63/1.93 b(x1) -> a(x1) 5.63/1.93 c(c(x1)) -> f(d(x1)) 5.63/1.93 d(d(x1)) -> f(f(f(x1))) 5.63/1.93 d(x1) -> b(x1) 5.63/1.93 f(f(x1)) -> a(g(x1)) 5.63/1.93 g(g(x1)) -> a(x1) 5.63/1.93 Matrix Interpretation Processor: dim=3 5.63/1.93 5.63/1.93 interpretation: 5.63/1.93 [1 1 0] [0] 5.63/1.93 [g](x0) = [0 0 1]x0 + [1] 5.63/1.93 [0 0 0] [0], 5.63/1.93 5.63/1.93 [1 1 0] 5.63/1.93 [f](x0) = [0 0 0]x0 5.63/1.93 [0 0 0] , 5.63/1.93 5.63/1.93 [1 0 1] 5.63/1.93 [d](x0) = [0 0 0]x0 5.63/1.93 [0 1 0] , 5.63/1.93 5.63/1.93 [1 0 1] 5.63/1.93 [b](x0) = [0 0 0]x0 5.63/1.93 [0 0 0] , 5.63/1.93 5.63/1.93 [1 0 1] 5.63/1.93 [c](x0) = [0 0 0]x0 5.63/1.93 [0 0 0] , 5.63/1.93 5.63/1.93 [1 0 1] 5.63/1.93 [a](x0) = [0 0 0]x0 5.63/1.93 [0 0 0] 5.63/1.93 orientation: 5.63/1.93 [1 0 1] [1 0 1] 5.63/1.93 a(a(x1)) = [0 0 0]x1 >= [0 0 0]x1 = c(b(x1)) 5.63/1.93 [0 0 0] [0 0 0] 5.63/1.93 5.63/1.93 [1 0 1] [1 0 1] 5.63/1.93 b(b(x1)) = [0 0 0]x1 >= [0 0 0]x1 = d(c(x1)) 5.63/1.93 [0 0 0] [0 0 0] 5.63/1.93 5.63/1.93 [1 0 1] [1 0 1] 5.63/1.93 b(x1) = [0 0 0]x1 >= [0 0 0]x1 = a(x1) 5.63/1.93 [0 0 0] [0 0 0] 5.63/1.93 5.63/1.93 [1 0 1] [1 0 1] 5.63/1.93 c(c(x1)) = [0 0 0]x1 >= [0 0 0]x1 = f(d(x1)) 5.63/1.93 [0 0 0] [0 0 0] 5.63/1.93 5.63/1.93 [1 1 1] [1 1 0] 5.63/1.93 d(d(x1)) = [0 0 0]x1 >= [0 0 0]x1 = f(f(f(x1))) 5.63/1.93 [0 0 0] [0 0 0] 5.63/1.93 5.63/1.93 [1 0 1] [1 0 1] 5.63/1.93 d(x1) = [0 0 0]x1 >= [0 0 0]x1 = b(x1) 5.63/1.93 [0 1 0] [0 0 0] 5.63/1.93 5.63/1.93 [1 1 0] [1 1 0] 5.63/1.93 f(f(x1)) = [0 0 0]x1 >= [0 0 0]x1 = a(g(x1)) 5.63/1.93 [0 0 0] [0 0 0] 5.63/1.93 5.63/1.93 [1 1 1] [1] [1 0 1] 5.63/1.93 g(g(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 = a(x1) 5.63/1.93 [0 0 0] [0] [0 0 0] 5.63/1.93 problem: 5.63/1.93 a(a(x1)) -> c(b(x1)) 5.63/1.93 b(b(x1)) -> d(c(x1)) 5.63/1.93 b(x1) -> a(x1) 5.63/1.93 c(c(x1)) -> f(d(x1)) 5.63/1.93 d(d(x1)) -> f(f(f(x1))) 5.63/1.93 d(x1) -> b(x1) 5.63/1.93 f(f(x1)) -> a(g(x1)) 5.63/1.93 String Reversal Processor: 5.63/1.93 a(a(x1)) -> b(c(x1)) 5.63/1.93 b(b(x1)) -> c(d(x1)) 5.63/1.93 b(x1) -> a(x1) 5.63/1.93 c(c(x1)) -> d(f(x1)) 5.63/1.93 d(d(x1)) -> f(f(f(x1))) 5.63/1.93 d(x1) -> b(x1) 5.63/1.93 f(f(x1)) -> g(a(x1)) 5.63/1.93 Matrix Interpretation Processor: dim=1 5.63/1.93 5.63/1.93 interpretation: 5.63/1.93 [g](x0) = x0,
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