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SRS_Standard 2019-03-29 03.29 pair #432294097
details
property
value
status
complete
benchmark
6.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n041.star.cs.uiowa.edu
space
Secret_06_SRS
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
8.3722 seconds
cpu usage
28.7234
user time
27.4111
system time
1.31221
max virtual memory
4.0715308E7
max residence set size
3876832.0
stage attributes
key
value
starexec-result
YES
output
26.07/7.51 YES 28.49/8.28 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 28.49/8.28 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 28.49/8.28 28.49/8.28 28.49/8.28 Termination w.r.t. Q of the given QTRS could be proven: 28.49/8.28 28.49/8.28 (0) QTRS 28.49/8.28 (1) QTRS Reverse [EQUIVALENT, 0 ms] 28.49/8.28 (2) QTRS 28.49/8.28 (3) DependencyPairsProof [EQUIVALENT, 10 ms] 28.49/8.28 (4) QDP 28.49/8.28 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 28.49/8.28 (6) QDP 28.49/8.28 (7) QDPOrderProof [EQUIVALENT, 35 ms] 28.49/8.28 (8) QDP 28.49/8.28 (9) QDPOrderProof [EQUIVALENT, 65 ms] 28.49/8.28 (10) QDP 28.49/8.28 (11) PisEmptyProof [EQUIVALENT, 0 ms] 28.49/8.28 (12) YES 28.49/8.28 28.49/8.28 28.49/8.28 ---------------------------------------- 28.49/8.28 28.49/8.28 (0) 28.49/8.28 Obligation: 28.49/8.28 Q restricted rewrite system: 28.49/8.28 The TRS R consists of the following rules: 28.49/8.28 28.49/8.28 a(a(a(b(x1)))) -> b(a(a(a(x1)))) 28.49/8.28 b(a(b(a(x1)))) -> a(b(b(a(x1)))) 28.49/8.28 28.49/8.28 Q is empty. 28.49/8.28 28.49/8.28 ---------------------------------------- 28.49/8.28 28.49/8.28 (1) QTRS Reverse (EQUIVALENT) 28.49/8.28 We applied the QTRS Reverse Processor [REVERSE]. 28.49/8.28 ---------------------------------------- 28.49/8.28 28.49/8.28 (2) 28.49/8.28 Obligation: 28.49/8.28 Q restricted rewrite system: 28.49/8.28 The TRS R consists of the following rules: 28.49/8.28 28.49/8.28 b(a(a(a(x1)))) -> a(a(a(b(x1)))) 28.49/8.28 a(b(a(b(x1)))) -> a(b(b(a(x1)))) 28.49/8.28 28.49/8.28 Q is empty. 28.49/8.28 28.49/8.28 ---------------------------------------- 28.49/8.28 28.49/8.28 (3) DependencyPairsProof (EQUIVALENT) 28.49/8.28 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 28.49/8.28 ---------------------------------------- 28.49/8.28 28.49/8.28 (4) 28.49/8.28 Obligation: 28.49/8.28 Q DP problem: 28.49/8.28 The TRS P consists of the following rules: 28.49/8.28 28.49/8.28 B(a(a(a(x1)))) -> A(a(a(b(x1)))) 28.49/8.28 B(a(a(a(x1)))) -> A(a(b(x1))) 28.49/8.28 B(a(a(a(x1)))) -> A(b(x1)) 28.49/8.28 B(a(a(a(x1)))) -> B(x1) 28.49/8.28 A(b(a(b(x1)))) -> A(b(b(a(x1)))) 28.49/8.28 A(b(a(b(x1)))) -> B(b(a(x1))) 28.49/8.28 A(b(a(b(x1)))) -> B(a(x1)) 28.49/8.28 A(b(a(b(x1)))) -> A(x1) 28.49/8.28 28.49/8.28 The TRS R consists of the following rules: 28.49/8.28 28.49/8.28 b(a(a(a(x1)))) -> a(a(a(b(x1)))) 28.49/8.28 a(b(a(b(x1)))) -> a(b(b(a(x1)))) 28.49/8.28 28.49/8.28 Q is empty. 28.49/8.28 We have to consider all minimal (P,Q,R)-chains. 28.49/8.28 ---------------------------------------- 28.49/8.28 28.49/8.28 (5) DependencyGraphProof (EQUIVALENT) 28.49/8.28 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. 28.49/8.28 ---------------------------------------- 28.49/8.28 28.49/8.28 (6) 28.49/8.28 Obligation: 28.49/8.28 Q DP problem: 28.49/8.28 The TRS P consists of the following rules: 28.49/8.28 28.49/8.28 B(a(a(a(x1)))) -> A(b(x1)) 28.49/8.28 A(b(a(b(x1)))) -> A(b(b(a(x1)))) 28.49/8.28 A(b(a(b(x1)))) -> B(b(a(x1))) 28.49/8.28 B(a(a(a(x1)))) -> B(x1) 28.49/8.28 A(b(a(b(x1)))) -> B(a(x1)) 28.49/8.28 A(b(a(b(x1)))) -> A(x1) 28.49/8.28 28.49/8.28 The TRS R consists of the following rules: 28.49/8.28 28.49/8.28 b(a(a(a(x1)))) -> a(a(a(b(x1)))) 28.49/8.28 a(b(a(b(x1)))) -> a(b(b(a(x1)))) 28.49/8.28
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