details

property	value
status	complete
benchmark	aprove00.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n145.star.cs.uiowa.edu
space	Secret_06_SRS

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	6.01592 seconds
cpu usage	19.7273
user time	18.8352
system time	0.892146
max virtual memory	2.1019228E7
max residence set size	2720096.0

stage attributes

key	value
starexec-result	YES

output

19.37/5.90 YES 19.61/5.96 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 19.61/5.96 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 19.61/5.96 19.61/5.96 19.61/5.96 Termination w.r.t. Q of the given QTRS could be proven: 19.61/5.96 19.61/5.96 (0) QTRS 19.61/5.96 (1) DependencyPairsProof [EQUIVALENT, 17 ms] 19.61/5.96 (2) QDP 19.61/5.96 (3) DependencyGraphProof [EQUIVALENT, 0 ms] 19.61/5.96 (4) AND 19.61/5.96 (5) QDP 19.61/5.96 (6) UsableRulesProof [EQUIVALENT, 2 ms] 19.61/5.96 (7) QDP 19.61/5.96 (8) QDPSizeChangeProof [EQUIVALENT, 2 ms] 19.61/5.96 (9) YES 19.61/5.96 (10) QDP 19.61/5.96 (11) MNOCProof [EQUIVALENT, 0 ms] 19.61/5.96 (12) QDP 19.61/5.96 (13) UsableRulesProof [EQUIVALENT, 0 ms] 19.61/5.96 (14) QDP 19.61/5.96 (15) QReductionProof [EQUIVALENT, 0 ms] 19.61/5.96 (16) QDP 19.61/5.96 (17) QDPOrderProof [EQUIVALENT, 34 ms] 19.61/5.96 (18) QDP 19.61/5.96 (19) DependencyGraphProof [EQUIVALENT, 0 ms] 19.61/5.96 (20) TRUE 19.61/5.96 19.61/5.96 19.61/5.96 ---------------------------------------- 19.61/5.96 19.61/5.96 (0) 19.61/5.96 Obligation: 19.61/5.96 Q restricted rewrite system: 19.61/5.96 The TRS R consists of the following rules: 19.61/5.96 19.61/5.96 a(s(x1)) -> s(s(s(p(s(b(p(p(s(s(x1)))))))))) 19.61/5.96 b(s(x1)) -> s(s(s(p(p(s(s(c(p(s(p(s(x1)))))))))))) 19.61/5.96 c(s(x1)) -> p(s(p(s(a(p(s(p(s(x1))))))))) 19.61/5.96 p(p(s(x1))) -> p(x1) 19.61/5.96 p(s(x1)) -> x1 19.61/5.96 19.61/5.96 Q is empty. 19.61/5.96 19.61/5.96 ---------------------------------------- 19.61/5.96 19.61/5.96 (1) DependencyPairsProof (EQUIVALENT) 19.61/5.96 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 19.61/5.96 ---------------------------------------- 19.61/5.96 19.61/5.96 (2) 19.61/5.96 Obligation: 19.61/5.96 Q DP problem: 19.61/5.96 The TRS P consists of the following rules: 19.61/5.96 19.61/5.96 A(s(x1)) -> P(s(b(p(p(s(s(x1))))))) 19.61/5.96 A(s(x1)) -> B(p(p(s(s(x1))))) 19.61/5.96 A(s(x1)) -> P(p(s(s(x1)))) 19.61/5.96 A(s(x1)) -> P(s(s(x1))) 19.61/5.96 B(s(x1)) -> P(p(s(s(c(p(s(p(s(x1))))))))) 19.61/5.96 B(s(x1)) -> P(s(s(c(p(s(p(s(x1)))))))) 19.61/5.96 B(s(x1)) -> C(p(s(p(s(x1))))) 19.61/5.96 B(s(x1)) -> P(s(p(s(x1)))) 19.61/5.96 B(s(x1)) -> P(s(x1)) 19.61/5.96 C(s(x1)) -> P(s(p(s(a(p(s(p(s(x1))))))))) 19.61/5.96 C(s(x1)) -> P(s(a(p(s(p(s(x1))))))) 19.61/5.96 C(s(x1)) -> A(p(s(p(s(x1))))) 19.61/5.96 C(s(x1)) -> P(s(p(s(x1)))) 19.61/5.96 C(s(x1)) -> P(s(x1)) 19.61/5.96 P(p(s(x1))) -> P(x1) 19.61/5.96 19.61/5.96 The TRS R consists of the following rules: 19.61/5.96 19.61/5.96 a(s(x1)) -> s(s(s(p(s(b(p(p(s(s(x1)))))))))) 19.61/5.96 b(s(x1)) -> s(s(s(p(p(s(s(c(p(s(p(s(x1)))))))))))) 19.61/5.96 c(s(x1)) -> p(s(p(s(a(p(s(p(s(x1))))))))) 19.61/5.96 p(p(s(x1))) -> p(x1) 19.61/5.96 p(s(x1)) -> x1 19.61/5.96 19.61/5.96 Q is empty. 19.61/5.96 We have to consider all minimal (P,Q,R)-chains. 19.61/5.96 ---------------------------------------- 19.61/5.96 19.61/5.96 (3) DependencyGraphProof (EQUIVALENT) 19.61/5.96 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 11 less nodes. 19.61/5.96 ---------------------------------------- 19.61/5.96 19.61/5.96 (4) 19.61/5.96 Complex Obligation (AND) 19.61/5.96 19.61/5.96 ---------------------------------------- 19.61/5.96 19.61/5.96 (5) 19.61/5.96 Obligation: 19.61/5.96 Q DP problem: 19.61/5.96 The TRS P consists of the following rules: 19.61/5.96 19.61/5.96 P(p(s(x1))) -> P(x1) 19.61/5.96 popout

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all output return to SRS_Standard 2019-03-29 03.29