details

property	value
status	complete
benchmark	un14.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n061.star.cs.uiowa.edu
space	Trafo_06

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	41.0684 seconds
cpu usage	158.039
user time	153.655
system time	4.38391
max virtual memory	4.1985704E7
max residence set size	8522300.0

stage attributes

key	value
starexec-result	YES

output

157.50/40.91 YES 157.70/41.01 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 157.70/41.01 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 157.70/41.01 157.70/41.01 157.70/41.01 Termination w.r.t. Q of the given QTRS could be proven: 157.70/41.01 157.70/41.01 (0) QTRS 157.70/41.01 (1) QTRS Reverse [EQUIVALENT, 0 ms] 157.70/41.01 (2) QTRS 157.70/41.01 (3) DependencyPairsProof [EQUIVALENT, 40 ms] 157.70/41.01 (4) QDP 157.70/41.01 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 157.70/41.01 (6) AND 157.70/41.01 (7) QDP 157.70/41.01 (8) QDPOrderProof [EQUIVALENT, 6792 ms] 157.70/41.01 (9) QDP 157.70/41.01 (10) PisEmptyProof [EQUIVALENT, 0 ms] 157.70/41.01 (11) YES 157.70/41.01 (12) QDP 157.70/41.01 (13) QDPOrderProof [EQUIVALENT, 6895 ms] 157.70/41.01 (14) QDP 157.70/41.01 (15) PisEmptyProof [EQUIVALENT, 0 ms] 157.70/41.01 (16) YES 157.70/41.01 157.70/41.01 157.70/41.01 ---------------------------------------- 157.70/41.01 157.70/41.01 (0) 157.70/41.01 Obligation: 157.70/41.01 Q restricted rewrite system: 157.70/41.01 The TRS R consists of the following rules: 157.70/41.01 157.70/41.01 b(a(b(x1))) -> b(a(a(a(b(x1))))) 157.70/41.01 b(a(a(a(b(a(a(b(x1)))))))) -> b(a(a(b(a(a(b(a(a(a(b(b(x1)))))))))))) 157.70/41.01 b(a(a(a(b(a(a(a(b(x1))))))))) -> b(x1) 157.70/41.01 b(a(a(a(b(b(b(x1))))))) -> b(b(b(a(a(a(b(x1))))))) 157.70/41.01 b(a(a(b(b(x1))))) -> b(x1) 157.70/41.01 b(b(a(a(b(x1))))) -> b(x1) 157.70/41.01 b(a(a(a(b(a(b(x1))))))) -> b(x1) 157.70/41.01 b(a(b(a(a(a(b(x1))))))) -> b(x1) 157.70/41.01 157.70/41.01 Q is empty. 157.70/41.01 157.70/41.01 ---------------------------------------- 157.70/41.01 157.70/41.01 (1) QTRS Reverse (EQUIVALENT) 157.70/41.01 We applied the QTRS Reverse Processor [REVERSE]. 157.70/41.01 ---------------------------------------- 157.70/41.01 157.70/41.01 (2) 157.70/41.01 Obligation: 157.70/41.01 Q restricted rewrite system: 157.70/41.01 The TRS R consists of the following rules: 157.70/41.01 157.70/41.01 b(a(b(x1))) -> b(a(a(a(b(x1))))) 157.70/41.01 b(a(a(b(a(a(a(b(x1)))))))) -> b(b(a(a(a(b(a(a(b(a(a(b(x1)))))))))))) 157.70/41.01 b(a(a(a(b(a(a(a(b(x1))))))))) -> b(x1) 157.70/41.01 b(b(b(a(a(a(b(x1))))))) -> b(a(a(a(b(b(b(x1))))))) 157.70/41.01 b(b(a(a(b(x1))))) -> b(x1) 157.70/41.01 b(a(a(b(b(x1))))) -> b(x1) 157.70/41.01 b(a(b(a(a(a(b(x1))))))) -> b(x1) 157.70/41.01 b(a(a(a(b(a(b(x1))))))) -> b(x1) 157.70/41.01 157.70/41.01 Q is empty. 157.70/41.01 157.70/41.01 ---------------------------------------- 157.70/41.01 157.70/41.01 (3) DependencyPairsProof (EQUIVALENT) 157.70/41.01 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 157.70/41.01 ---------------------------------------- 157.70/41.01 157.70/41.01 (4) 157.70/41.01 Obligation: 157.70/41.01 Q DP problem: 157.70/41.01 The TRS P consists of the following rules: 157.70/41.01 157.70/41.01 B(a(b(x1))) -> B(a(a(a(b(x1))))) 157.70/41.01 B(a(a(b(a(a(a(b(x1)))))))) -> B(b(a(a(a(b(a(a(b(a(a(b(x1)))))))))))) 157.70/41.01 B(a(a(b(a(a(a(b(x1)))))))) -> B(a(a(a(b(a(a(b(a(a(b(x1))))))))))) 157.70/41.01 B(a(a(b(a(a(a(b(x1)))))))) -> B(a(a(b(a(a(b(x1))))))) 157.70/41.01 B(a(a(b(a(a(a(b(x1)))))))) -> B(a(a(b(x1)))) 157.70/41.01 B(b(b(a(a(a(b(x1))))))) -> B(a(a(a(b(b(b(x1))))))) 157.70/41.01 B(b(b(a(a(a(b(x1))))))) -> B(b(b(x1))) 157.70/41.01 B(b(b(a(a(a(b(x1))))))) -> B(b(x1)) 157.70/41.01 157.70/41.01 The TRS R consists of the following rules: 157.70/41.01 157.70/41.01 b(a(b(x1))) -> b(a(a(a(b(x1))))) 157.70/41.01 b(a(a(b(a(a(a(b(x1)))))))) -> b(b(a(a(a(b(a(a(b(a(a(b(x1)))))))))))) 157.70/41.01 b(a(a(a(b(a(a(a(b(x1))))))))) -> b(x1) 157.70/41.01 b(b(b(a(a(a(b(x1))))))) -> b(a(a(a(b(b(b(x1))))))) 157.70/41.01 b(b(a(a(b(x1))))) -> b(x1) 157.70/41.01 b(a(a(b(b(x1))))) -> b(x1) 157.70/41.01 b(a(b(a(a(a(b(x1))))))) -> b(x1) 157.70/41.01 b(a(a(a(b(a(b(x1))))))) -> b(x1) 157.70/41.01 157.70/41.01 Q is empty. 157.70/41.01 We have to consider all minimal (P,Q,R)-chains. 157.70/41.01 ---------------------------------------- popout

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