details

property	value
status	complete
benchmark	dup15.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n047.star.cs.uiowa.edu
space	Trafo_06

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	9.07192 seconds
cpu usage	31.3362
user time	30.0351
system time	1.30115
max virtual memory	4.1892272E7
max residence set size	3959900.0

stage attributes

key	value
starexec-result	YES

output

30.63/8.96 YES 31.15/8.99 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 31.15/8.99 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 31.15/8.99 31.15/8.99 31.15/8.99 Termination w.r.t. Q of the given QTRS could be proven: 31.15/8.99 31.15/8.99 (0) QTRS 31.15/8.99 (1) DependencyPairsProof [EQUIVALENT, 18 ms] 31.15/8.99 (2) QDP 31.15/8.99 (3) DependencyGraphProof [EQUIVALENT, 0 ms] 31.15/8.99 (4) QDP 31.15/8.99 (5) QDPOrderProof [EQUIVALENT, 120 ms] 31.15/8.99 (6) QDP 31.15/8.99 (7) MRRProof [EQUIVALENT, 31 ms] 31.15/8.99 (8) QDP 31.15/8.99 (9) QDPOrderProof [EQUIVALENT, 48 ms] 31.15/8.99 (10) QDP 31.15/8.99 (11) QDPOrderProof [EQUIVALENT, 0 ms] 31.15/8.99 (12) QDP 31.15/8.99 (13) DependencyGraphProof [EQUIVALENT, 0 ms] 31.15/8.99 (14) TRUE 31.15/8.99 31.15/8.99 31.15/8.99 ---------------------------------------- 31.15/8.99 31.15/8.99 (0) 31.15/8.99 Obligation: 31.15/8.99 Q restricted rewrite system: 31.15/8.99 The TRS R consists of the following rules: 31.15/8.99 31.15/8.99 a(a(d(d(x1)))) -> d(d(b(b(x1)))) 31.15/8.99 a(a(x1)) -> b(b(b(b(b(b(x1)))))) 31.15/8.99 b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) 31.15/8.99 c(c(x1)) -> d(d(x1)) 31.15/8.99 31.15/8.99 Q is empty. 31.15/8.99 31.15/8.99 ---------------------------------------- 31.15/8.99 31.15/8.99 (1) DependencyPairsProof (EQUIVALENT) 31.15/8.99 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 31.15/8.99 ---------------------------------------- 31.15/8.99 31.15/8.99 (2) 31.15/8.99 Obligation: 31.15/8.99 Q DP problem: 31.15/8.99 The TRS P consists of the following rules: 31.15/8.99 31.15/8.99 A(a(d(d(x1)))) -> B(b(x1)) 31.15/8.99 A(a(d(d(x1)))) -> B(x1) 31.15/8.99 A(a(x1)) -> B(b(b(b(b(b(x1)))))) 31.15/8.99 A(a(x1)) -> B(b(b(b(b(x1))))) 31.15/8.99 A(a(x1)) -> B(b(b(b(x1)))) 31.15/8.99 A(a(x1)) -> B(b(b(x1))) 31.15/8.99 A(a(x1)) -> B(b(x1)) 31.15/8.99 A(a(x1)) -> B(x1) 31.15/8.99 B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) 31.15/8.99 B(b(d(d(b(b(x1)))))) -> A(c(c(x1))) 31.15/8.99 B(b(d(d(b(b(x1)))))) -> C(c(x1)) 31.15/8.99 B(b(d(d(b(b(x1)))))) -> C(x1) 31.15/8.99 31.15/8.99 The TRS R consists of the following rules: 31.15/8.99 31.15/8.99 a(a(d(d(x1)))) -> d(d(b(b(x1)))) 31.15/8.99 a(a(x1)) -> b(b(b(b(b(b(x1)))))) 31.15/8.99 b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) 31.15/8.99 c(c(x1)) -> d(d(x1)) 31.15/8.99 31.15/8.99 Q is empty. 31.15/8.99 We have to consider all minimal (P,Q,R)-chains. 31.15/8.99 ---------------------------------------- 31.15/8.99 31.15/8.99 (3) DependencyGraphProof (EQUIVALENT) 31.15/8.99 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. 31.15/8.99 ---------------------------------------- 31.15/8.99 31.15/8.99 (4) 31.15/8.99 Obligation: 31.15/8.99 Q DP problem: 31.15/8.99 The TRS P consists of the following rules: 31.15/8.99 31.15/8.99 B(b(d(d(b(b(x1)))))) -> A(a(c(c(x1)))) 31.15/8.99 A(a(d(d(x1)))) -> B(b(x1)) 31.15/8.99 B(b(d(d(b(b(x1)))))) -> A(c(c(x1))) 31.15/8.99 A(a(d(d(x1)))) -> B(x1) 31.15/8.99 A(a(x1)) -> B(b(b(b(b(b(x1)))))) 31.15/8.99 A(a(x1)) -> B(b(b(b(b(x1))))) 31.15/8.99 A(a(x1)) -> B(b(b(b(x1)))) 31.15/8.99 A(a(x1)) -> B(b(b(x1))) 31.15/8.99 A(a(x1)) -> B(b(x1)) 31.15/8.99 A(a(x1)) -> B(x1) 31.15/8.99 31.15/8.99 The TRS R consists of the following rules: 31.15/8.99 31.15/8.99 a(a(d(d(x1)))) -> d(d(b(b(x1)))) 31.15/8.99 a(a(x1)) -> b(b(b(b(b(b(x1)))))) 31.15/8.99 b(b(d(d(b(b(x1)))))) -> a(a(c(c(x1)))) 31.15/8.99 c(c(x1)) -> d(d(x1)) 31.15/8.99 popout

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all output return to SRS_Standard 2019-03-29 03.29