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SRS_Standard 2019-03-29 03.29 pair #432294408
details
property
value
status
complete
benchmark
dup17.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n013.star.cs.uiowa.edu
space
Trafo_06
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
1.84819 seconds
cpu usage
5.97454
user time
4.9084
system time
1.06615
max virtual memory
3628412.0
max residence set size
70820.0
stage attributes
key
value
starexec-result
YES
output
5.28/1.84 YES 5.28/1.84 5.28/1.84 Problem: 5.28/1.84 a(a(a(a(x1)))) -> b(b(x1)) 5.28/1.84 b(b(a(a(x1)))) -> a(a(b(b(x1)))) 5.28/1.84 b(b(b(b(c(c(x1)))))) -> c(c(a(a(x1)))) 5.28/1.84 b(b(b(b(x1)))) -> a(a(a(a(a(a(x1)))))) 5.28/1.84 c(c(a(a(x1)))) -> b(b(a(a(c(c(x1)))))) 5.28/1.84 5.28/1.84 Proof: 5.28/1.84 Matrix Interpretation Processor: dim=1 5.28/1.84 5.28/1.84 interpretation: 5.28/1.84 [c](x0) = 2x0 + 1, 5.28/1.84 5.28/1.84 [b](x0) = x0 + 4, 5.28/1.84 5.28/1.84 [a](x0) = x0 + 2 5.28/1.84 orientation: 5.28/1.84 a(a(a(a(x1)))) = x1 + 8 >= x1 + 8 = b(b(x1)) 5.28/1.84 5.28/1.84 b(b(a(a(x1)))) = x1 + 12 >= x1 + 12 = a(a(b(b(x1)))) 5.28/1.84 5.28/1.84 b(b(b(b(c(c(x1)))))) = 4x1 + 19 >= 4x1 + 19 = c(c(a(a(x1)))) 5.28/1.84 5.28/1.84 b(b(b(b(x1)))) = x1 + 16 >= x1 + 12 = a(a(a(a(a(a(x1)))))) 5.28/1.84 5.28/1.84 c(c(a(a(x1)))) = 4x1 + 19 >= 4x1 + 15 = b(b(a(a(c(c(x1)))))) 5.28/1.84 problem: 5.28/1.84 a(a(a(a(x1)))) -> b(b(x1)) 5.28/1.84 b(b(a(a(x1)))) -> a(a(b(b(x1)))) 5.28/1.84 b(b(b(b(c(c(x1)))))) -> c(c(a(a(x1)))) 5.28/1.84 KBO Processor: 5.28/1.84 weight function: 5.28/1.84 w0 = 1 5.28/1.84 w(c) = w(b) = w(a) = 1 5.28/1.84 precedence: 5.28/1.84 b > c ~ a 5.28/1.84 problem: 5.28/1.84 5.28/1.84 Qed 5.28/1.84 EOF
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