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SRS_Standard 2019-03-29 03.29 pair #432294409
details
property
value
status
complete
benchmark
un05.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n140.star.cs.uiowa.edu
space
Trafo_06
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
8.96212 seconds
cpu usage
31.6743
user time
30.2942
system time
1.38003
max virtual memory
6.0401412E7
max residence set size
4168604.0
stage attributes
key
value
starexec-result
YES
output
31.39/8.87 YES 31.39/8.90 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 31.39/8.90 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 31.39/8.90 31.39/8.90 31.39/8.90 Termination w.r.t. Q of the given QTRS could be proven: 31.39/8.90 31.39/8.90 (0) QTRS 31.39/8.90 (1) QTRS Reverse [EQUIVALENT, 0 ms] 31.39/8.90 (2) QTRS 31.39/8.90 (3) DependencyPairsProof [EQUIVALENT, 1 ms] 31.39/8.90 (4) QDP 31.39/8.90 (5) QDPOrderProof [EQUIVALENT, 131 ms] 31.39/8.90 (6) QDP 31.39/8.90 (7) QDPOrderProof [EQUIVALENT, 1000 ms] 31.39/8.90 (8) QDP 31.39/8.90 (9) DependencyGraphProof [EQUIVALENT, 0 ms] 31.39/8.90 (10) TRUE 31.39/8.90 31.39/8.90 31.39/8.90 ---------------------------------------- 31.39/8.90 31.39/8.90 (0) 31.39/8.90 Obligation: 31.39/8.90 Q restricted rewrite system: 31.39/8.90 The TRS R consists of the following rules: 31.39/8.90 31.39/8.90 b(b(b(b(x1)))) -> b(b(b(a(b(x1))))) 31.39/8.90 b(a(b(b(a(b(x1)))))) -> b(b(a(b(b(x1))))) 31.39/8.90 31.39/8.90 Q is empty. 31.39/8.90 31.39/8.90 ---------------------------------------- 31.39/8.90 31.39/8.90 (1) QTRS Reverse (EQUIVALENT) 31.39/8.90 We applied the QTRS Reverse Processor [REVERSE]. 31.39/8.90 ---------------------------------------- 31.39/8.90 31.39/8.90 (2) 31.39/8.90 Obligation: 31.39/8.90 Q restricted rewrite system: 31.39/8.90 The TRS R consists of the following rules: 31.39/8.90 31.39/8.90 b(b(b(b(x1)))) -> b(a(b(b(b(x1))))) 31.39/8.90 b(a(b(b(a(b(x1)))))) -> b(b(a(b(b(x1))))) 31.39/8.90 31.39/8.90 Q is empty. 31.39/8.90 31.39/8.90 ---------------------------------------- 31.39/8.90 31.39/8.90 (3) DependencyPairsProof (EQUIVALENT) 31.39/8.90 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 31.39/8.90 ---------------------------------------- 31.39/8.90 31.39/8.90 (4) 31.39/8.90 Obligation: 31.39/8.90 Q DP problem: 31.39/8.90 The TRS P consists of the following rules: 31.39/8.90 31.39/8.90 B(b(b(b(x1)))) -> B(a(b(b(b(x1))))) 31.39/8.90 B(a(b(b(a(b(x1)))))) -> B(b(a(b(b(x1))))) 31.39/8.90 B(a(b(b(a(b(x1)))))) -> B(a(b(b(x1)))) 31.39/8.90 B(a(b(b(a(b(x1)))))) -> B(b(x1)) 31.39/8.90 31.39/8.90 The TRS R consists of the following rules: 31.39/8.90 31.39/8.90 b(b(b(b(x1)))) -> b(a(b(b(b(x1))))) 31.39/8.90 b(a(b(b(a(b(x1)))))) -> b(b(a(b(b(x1))))) 31.39/8.90 31.39/8.90 Q is empty. 31.39/8.90 We have to consider all minimal (P,Q,R)-chains. 31.39/8.90 ---------------------------------------- 31.39/8.90 31.39/8.90 (5) QDPOrderProof (EQUIVALENT) 31.39/8.90 We use the reduction pair processor [LPAR04,JAR06]. 31.39/8.90 31.39/8.90 31.39/8.90 The following pairs can be oriented strictly and are deleted. 31.39/8.90 31.39/8.90 B(a(b(b(a(b(x1)))))) -> B(a(b(b(x1)))) 31.39/8.90 B(a(b(b(a(b(x1)))))) -> B(b(x1)) 31.39/8.90 The remaining pairs can at least be oriented weakly. 31.39/8.90 Used ordering: Polynomial interpretation [POLO]: 31.39/8.90 31.39/8.90 POL(B(x_1)) = 2*x_1 31.39/8.90 POL(a(x_1)) = x_1 31.39/8.90 POL(b(x_1)) = 1 + x_1 31.39/8.90 31.39/8.90 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 31.39/8.90 31.39/8.90 b(a(b(b(a(b(x1)))))) -> b(b(a(b(b(x1))))) 31.39/8.90 b(b(b(b(x1)))) -> b(a(b(b(b(x1))))) 31.39/8.90 31.39/8.90 31.39/8.90 ---------------------------------------- 31.39/8.90 31.39/8.90 (6) 31.39/8.90 Obligation: 31.39/8.90 Q DP problem: 31.39/8.90 The TRS P consists of the following rules:
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