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SRS_Standard 2019-03-29 03.29 pair #432294493
details
property
value
status
complete
benchmark
random-470.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n061.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
4.4398 seconds
cpu usage
13.9728
user time
13.302
system time
0.670791
max virtual memory
5.9611116E7
max residence set size
2064576.0
stage attributes
key
value
starexec-result
YES
output
13.04/4.24 YES 13.68/4.35 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 13.68/4.35 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 13.68/4.35 13.68/4.35 13.68/4.35 Termination w.r.t. Q of the given QTRS could be proven: 13.68/4.35 13.68/4.35 (0) QTRS 13.68/4.35 (1) FlatCCProof [EQUIVALENT, 0 ms] 13.68/4.35 (2) QTRS 13.68/4.35 (3) RootLabelingProof [EQUIVALENT, 0 ms] 13.68/4.35 (4) QTRS 13.68/4.35 (5) DependencyPairsProof [EQUIVALENT, 2 ms] 13.68/4.35 (6) QDP 13.68/4.35 (7) DependencyGraphProof [EQUIVALENT, 0 ms] 13.68/4.35 (8) AND 13.68/4.35 (9) QDP 13.68/4.35 (10) UsableRulesProof [EQUIVALENT, 3 ms] 13.68/4.35 (11) QDP 13.68/4.35 (12) QDPOrderProof [EQUIVALENT, 39 ms] 13.68/4.35 (13) QDP 13.68/4.35 (14) DependencyGraphProof [EQUIVALENT, 0 ms] 13.68/4.35 (15) TRUE 13.68/4.35 (16) QDP 13.68/4.35 (17) UsableRulesProof [EQUIVALENT, 2 ms] 13.68/4.35 (18) QDP 13.68/4.35 (19) QDPSizeChangeProof [EQUIVALENT, 1 ms] 13.68/4.35 (20) YES 13.68/4.35 13.68/4.35 13.68/4.35 ---------------------------------------- 13.68/4.35 13.68/4.35 (0) 13.68/4.35 Obligation: 13.68/4.35 Q restricted rewrite system: 13.68/4.35 The TRS R consists of the following rules: 13.68/4.35 13.68/4.35 a(b(a(a(x1)))) -> a(b(b(a(x1)))) 13.68/4.35 a(b(a(b(x1)))) -> a(b(b(a(x1)))) 13.68/4.35 b(b(a(a(x1)))) -> a(b(a(a(x1)))) 13.68/4.35 b(b(b(b(x1)))) -> a(a(a(a(x1)))) 13.68/4.35 13.68/4.35 Q is empty. 13.68/4.35 13.68/4.35 ---------------------------------------- 13.68/4.35 13.68/4.35 (1) FlatCCProof (EQUIVALENT) 13.68/4.35 We used flat context closure [ROOTLAB] 13.68/4.35 As Q is empty the flat context closure was sound AND complete. 13.68/4.35 13.68/4.35 ---------------------------------------- 13.68/4.35 13.68/4.35 (2) 13.68/4.35 Obligation: 13.68/4.35 Q restricted rewrite system: 13.68/4.35 The TRS R consists of the following rules: 13.68/4.35 13.68/4.35 a(b(a(a(x1)))) -> a(b(b(a(x1)))) 13.68/4.35 a(b(a(b(x1)))) -> a(b(b(a(x1)))) 13.68/4.35 a(b(b(a(a(x1))))) -> a(a(b(a(a(x1))))) 13.68/4.35 b(b(b(a(a(x1))))) -> b(a(b(a(a(x1))))) 13.68/4.35 a(b(b(b(b(x1))))) -> a(a(a(a(a(x1))))) 13.68/4.35 b(b(b(b(b(x1))))) -> b(a(a(a(a(x1))))) 13.68/4.35 13.68/4.35 Q is empty. 13.68/4.35 13.68/4.35 ---------------------------------------- 13.68/4.35 13.68/4.35 (3) RootLabelingProof (EQUIVALENT) 13.68/4.35 We used plain root labeling [ROOTLAB] with the following heuristic: 13.68/4.35 LabelAll: All function symbols get labeled 13.68/4.35 13.68/4.35 As Q is empty the root labeling was sound AND complete. 13.68/4.35 13.68/4.35 ---------------------------------------- 13.68/4.35 13.68/4.35 (4) 13.68/4.35 Obligation: 13.68/4.35 Q restricted rewrite system: 13.68/4.35 The TRS R consists of the following rules: 13.68/4.35 13.68/4.35 a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(x1)))) 13.68/4.35 a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{a_1}(a_{b_1}(x1)))) 13.68/4.35 a_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(x1)))) 13.68/4.35 a_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{a_1}(a_{b_1}(x1)))) 13.68/4.35 a_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1))))) -> a_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1))))) 13.68/4.35 a_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1))))) -> a_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1))))) 13.68/4.35 b_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1))))) -> b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1))))) 13.68/4.35 b_{b_1}(b_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1))))) -> b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1))))) 13.68/4.35 a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> a_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(x1))))) 13.68/4.35 a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> a_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1))))) 13.68/4.35 b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(x1))))) 13.68/4.35 b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> b_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1))))) 13.68/4.35 13.68/4.35 Q is empty. 13.68/4.35 13.68/4.35 ---------------------------------------- 13.68/4.35 13.68/4.35 (5) DependencyPairsProof (EQUIVALENT) 13.68/4.35 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
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