details

property	value
status	complete
benchmark	random-132.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n182.star.cs.uiowa.edu
space	Waldmann_19

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	8.72618 seconds
cpu usage	30.1077
user time	28.55
system time	1.55768
max virtual memory	4.1676708E7
max residence set size	4111308.0

stage attributes

key	value
starexec-result	YES

output

29.55/8.54 YES 29.55/8.58 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 29.55/8.58 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 29.55/8.58 29.55/8.58 29.55/8.58 Termination w.r.t. Q of the given QTRS could be proven: 29.55/8.58 29.55/8.58 (0) QTRS 29.55/8.58 (1) DependencyPairsProof [EQUIVALENT, 16 ms] 29.55/8.58 (2) QDP 29.55/8.58 (3) QDPOrderProof [EQUIVALENT, 120 ms] 29.55/8.58 (4) QDP 29.55/8.58 (5) QDPOrderProof [EQUIVALENT, 251 ms] 29.55/8.58 (6) QDP 29.55/8.58 (7) PisEmptyProof [EQUIVALENT, 0 ms] 29.55/8.58 (8) YES 29.55/8.58 29.55/8.58 29.55/8.58 ---------------------------------------- 29.55/8.58 29.55/8.58 (0) 29.55/8.58 Obligation: 29.55/8.58 Q restricted rewrite system: 29.55/8.58 The TRS R consists of the following rules: 29.55/8.58 29.55/8.58 b(b(a(b(x1)))) -> a(b(b(b(x1)))) 29.55/8.58 a(a(a(b(x1)))) -> a(b(b(a(x1)))) 29.55/8.58 b(a(a(b(x1)))) -> a(a(a(b(x1)))) 29.55/8.58 29.55/8.58 Q is empty. 29.55/8.58 29.55/8.58 ---------------------------------------- 29.55/8.58 29.55/8.58 (1) DependencyPairsProof (EQUIVALENT) 29.55/8.58 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 29.55/8.58 ---------------------------------------- 29.55/8.58 29.55/8.58 (2) 29.55/8.58 Obligation: 29.55/8.58 Q DP problem: 29.55/8.58 The TRS P consists of the following rules: 29.55/8.58 29.55/8.58 B(b(a(b(x1)))) -> A(b(b(b(x1)))) 29.55/8.58 B(b(a(b(x1)))) -> B(b(b(x1))) 29.55/8.58 B(b(a(b(x1)))) -> B(b(x1)) 29.55/8.58 A(a(a(b(x1)))) -> A(b(b(a(x1)))) 29.55/8.58 A(a(a(b(x1)))) -> B(b(a(x1))) 29.55/8.58 A(a(a(b(x1)))) -> B(a(x1)) 29.55/8.58 A(a(a(b(x1)))) -> A(x1) 29.55/8.58 B(a(a(b(x1)))) -> A(a(a(b(x1)))) 29.55/8.58 29.55/8.58 The TRS R consists of the following rules: 29.55/8.58 29.55/8.58 b(b(a(b(x1)))) -> a(b(b(b(x1)))) 29.55/8.58 a(a(a(b(x1)))) -> a(b(b(a(x1)))) 29.55/8.58 b(a(a(b(x1)))) -> a(a(a(b(x1)))) 29.55/8.58 29.55/8.58 Q is empty. 29.55/8.58 We have to consider all minimal (P,Q,R)-chains. 29.55/8.58 ---------------------------------------- 29.55/8.58 29.55/8.58 (3) QDPOrderProof (EQUIVALENT) 29.55/8.58 We use the reduction pair processor [LPAR04,JAR06]. 29.55/8.58 29.55/8.58 29.55/8.58 The following pairs can be oriented strictly and are deleted. 29.55/8.58 29.55/8.58 B(b(a(b(x1)))) -> A(b(b(b(x1)))) 29.55/8.58 B(b(a(b(x1)))) -> B(b(b(x1))) 29.55/8.58 B(b(a(b(x1)))) -> B(b(x1)) 29.55/8.58 A(a(a(b(x1)))) -> B(b(a(x1))) 29.55/8.58 A(a(a(b(x1)))) -> B(a(x1)) 29.55/8.58 A(a(a(b(x1)))) -> A(x1) 29.55/8.58 B(a(a(b(x1)))) -> A(a(a(b(x1)))) 29.55/8.58 The remaining pairs can at least be oriented weakly. 29.55/8.58 Used ordering: Polynomial interpretation [POLO]: 29.55/8.58 29.55/8.58 POL(A(x_1)) = 4 + 2*x_1 29.55/8.58 POL(B(x_1)) = 1 + 4*x_1 29.55/8.58 POL(a(x_1)) = 2 + 2*x_1 29.55/8.58 POL(b(x_1)) = 2 + 2*x_1 29.55/8.58 29.55/8.58 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 29.55/8.58 29.55/8.58 b(b(a(b(x1)))) -> a(b(b(b(x1)))) 29.55/8.58 b(a(a(b(x1)))) -> a(a(a(b(x1)))) 29.55/8.58 a(a(a(b(x1)))) -> a(b(b(a(x1)))) 29.55/8.58 29.55/8.58 29.55/8.58 ---------------------------------------- 29.55/8.58 29.55/8.58 (4) 29.55/8.58 Obligation: 29.55/8.58 Q DP problem: 29.55/8.58 The TRS P consists of the following rules: 29.55/8.58 29.55/8.58 A(a(a(b(x1)))) -> A(b(b(a(x1)))) 29.55/8.58 29.55/8.58 The TRS R consists of the following rules: 29.55/8.58 popout

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all output return to SRS_Standard 2019-03-29 03.29