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SRS_Standard 2019-03-29 03.29 pair #432294714
details
property
value
status
complete
benchmark
random-436.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n176.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
2.19269 seconds
cpu usage
7.31596
user time
5.61882
system time
1.69714
max virtual memory
3580084.0
max residence set size
68872.0
stage attributes
key
value
starexec-result
YES
output
6.49/2.18 YES 6.49/2.18 6.49/2.18 Problem: 6.49/2.18 a(b(b(a(x1)))) -> a(b(a(b(x1)))) 6.49/2.18 a(a(b(a(x1)))) -> a(b(b(a(x1)))) 6.49/2.18 a(a(b(b(x1)))) -> b(b(a(a(x1)))) 6.49/2.18 6.49/2.18 Proof: 6.49/2.18 Matrix Interpretation Processor: dim=1 6.49/2.18 6.49/2.18 interpretation: 6.49/2.18 [b](x0) = x0, 6.49/2.18 6.49/2.18 [a](x0) = 2x0 + 2 6.49/2.18 orientation: 6.49/2.18 a(b(b(a(x1)))) = 4x1 + 6 >= 4x1 + 6 = a(b(a(b(x1)))) 6.49/2.18 6.49/2.18 a(a(b(a(x1)))) = 8x1 + 14 >= 4x1 + 6 = a(b(b(a(x1)))) 6.49/2.18 6.49/2.18 a(a(b(b(x1)))) = 4x1 + 6 >= 4x1 + 6 = b(b(a(a(x1)))) 6.49/2.18 problem: 6.49/2.18 a(b(b(a(x1)))) -> a(b(a(b(x1)))) 6.49/2.18 a(a(b(b(x1)))) -> b(b(a(a(x1)))) 6.49/2.18 String Reversal Processor: 6.49/2.18 a(b(b(a(x1)))) -> b(a(b(a(x1)))) 6.49/2.18 b(b(a(a(x1)))) -> a(a(b(b(x1)))) 6.49/2.18 Matrix Interpretation Processor: dim=3 6.49/2.18 6.49/2.18 interpretation: 6.49/2.18 [1 0 0] 6.49/2.18 [b](x0) = [0 0 1]x0 6.49/2.18 [0 1 0] , 6.49/2.18 6.49/2.18 [1 0 1] [0] 6.49/2.18 [a](x0) = [0 0 1]x0 + [0] 6.49/2.18 [0 0 1] [1] 6.49/2.18 orientation: 6.49/2.18 [1 0 2] [1] [1 0 2] [0] 6.49/2.18 a(b(b(a(x1)))) = [0 0 1]x1 + [1] >= [0 0 1]x1 + [1] = b(a(b(a(x1)))) 6.49/2.18 [0 0 1] [2] [0 0 1] [0] 6.49/2.18 6.49/2.18 [1 0 2] [1] [1 0 2] [1] 6.49/2.18 b(b(a(a(x1)))) = [0 0 1]x1 + [1] >= [0 0 1]x1 + [1] = a(a(b(b(x1)))) 6.49/2.18 [0 0 1] [2] [0 0 1] [2] 6.49/2.18 problem: 6.49/2.18 b(b(a(a(x1)))) -> a(a(b(b(x1)))) 6.49/2.18 KBO Processor: 6.49/2.18 weight function: 6.49/2.18 w0 = 1 6.49/2.18 w(b) = w(a) = 1 6.49/2.18 precedence: 6.49/2.18 b > a 6.49/2.18 problem: 6.49/2.18 6.49/2.18 Qed 6.49/2.19 EOF
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