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SRS_Standard 2019-03-29 03.29 pair #432294865
details
property
value
status
complete
benchmark
random-194.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n142.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
10.6467 seconds
cpu usage
38.0285
user time
36.4354
system time
1.59312
max virtual memory
2.1155296E7
max residence set size
4218220.0
stage attributes
key
value
starexec-result
YES
output
37.82/10.57 YES 37.82/10.59 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 37.82/10.59 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 37.82/10.59 37.82/10.59 37.82/10.59 Termination w.r.t. Q of the given QTRS could be proven: 37.82/10.59 37.82/10.59 (0) QTRS 37.82/10.59 (1) DependencyPairsProof [EQUIVALENT, 21 ms] 37.82/10.59 (2) QDP 37.82/10.59 (3) DependencyGraphProof [EQUIVALENT, 8 ms] 37.82/10.59 (4) QDP 37.82/10.59 (5) MRRProof [EQUIVALENT, 59 ms] 37.82/10.59 (6) QDP 37.82/10.59 (7) DependencyGraphProof [EQUIVALENT, 0 ms] 37.82/10.59 (8) AND 37.82/10.59 (9) QDP 37.82/10.59 (10) QDPOrderProof [EQUIVALENT, 118 ms] 37.82/10.59 (11) QDP 37.82/10.59 (12) PisEmptyProof [EQUIVALENT, 0 ms] 37.82/10.59 (13) YES 37.82/10.59 (14) QDP 37.82/10.59 (15) QDPOrderProof [EQUIVALENT, 416 ms] 37.82/10.59 (16) QDP 37.82/10.59 (17) PisEmptyProof [EQUIVALENT, 0 ms] 37.82/10.59 (18) YES 37.82/10.59 37.82/10.59 37.82/10.59 ---------------------------------------- 37.82/10.59 37.82/10.59 (0) 37.82/10.59 Obligation: 37.82/10.59 Q restricted rewrite system: 37.82/10.59 The TRS R consists of the following rules: 37.82/10.59 37.82/10.59 b(b(a(a(x1)))) -> b(b(a(b(x1)))) 37.82/10.59 a(a(b(b(x1)))) -> b(b(a(a(x1)))) 37.82/10.59 b(a(a(b(x1)))) -> b(a(a(a(x1)))) 37.82/10.59 37.82/10.59 Q is empty. 37.82/10.59 37.82/10.59 ---------------------------------------- 37.82/10.59 37.82/10.59 (1) DependencyPairsProof (EQUIVALENT) 37.82/10.59 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 37.82/10.59 ---------------------------------------- 37.82/10.59 37.82/10.59 (2) 37.82/10.59 Obligation: 37.82/10.59 Q DP problem: 37.82/10.59 The TRS P consists of the following rules: 37.82/10.59 37.82/10.59 B(b(a(a(x1)))) -> B(b(a(b(x1)))) 37.82/10.59 B(b(a(a(x1)))) -> B(a(b(x1))) 37.82/10.59 B(b(a(a(x1)))) -> A(b(x1)) 37.82/10.59 B(b(a(a(x1)))) -> B(x1) 37.82/10.59 A(a(b(b(x1)))) -> B(b(a(a(x1)))) 37.82/10.59 A(a(b(b(x1)))) -> B(a(a(x1))) 37.82/10.59 A(a(b(b(x1)))) -> A(a(x1)) 37.82/10.59 A(a(b(b(x1)))) -> A(x1) 37.82/10.59 B(a(a(b(x1)))) -> B(a(a(a(x1)))) 37.82/10.59 B(a(a(b(x1)))) -> A(a(a(x1))) 37.82/10.59 B(a(a(b(x1)))) -> A(a(x1)) 37.82/10.59 B(a(a(b(x1)))) -> A(x1) 37.82/10.59 37.82/10.59 The TRS R consists of the following rules: 37.82/10.59 37.82/10.59 b(b(a(a(x1)))) -> b(b(a(b(x1)))) 37.82/10.59 a(a(b(b(x1)))) -> b(b(a(a(x1)))) 37.82/10.59 b(a(a(b(x1)))) -> b(a(a(a(x1)))) 37.82/10.59 37.82/10.59 Q is empty. 37.82/10.59 We have to consider all minimal (P,Q,R)-chains. 37.82/10.59 ---------------------------------------- 37.82/10.59 37.82/10.59 (3) DependencyGraphProof (EQUIVALENT) 37.82/10.59 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. 37.82/10.59 ---------------------------------------- 37.82/10.59 37.82/10.59 (4) 37.82/10.59 Obligation: 37.82/10.59 Q DP problem: 37.82/10.59 The TRS P consists of the following rules: 37.82/10.59 37.82/10.59 B(b(a(a(x1)))) -> B(a(b(x1))) 37.82/10.59 B(b(a(a(x1)))) -> B(b(a(b(x1)))) 37.82/10.59 B(b(a(a(x1)))) -> B(x1) 37.82/10.59 B(a(a(b(x1)))) -> B(a(a(a(x1)))) 37.82/10.59 B(a(a(b(x1)))) -> A(a(a(x1))) 37.82/10.59 A(a(b(b(x1)))) -> B(b(a(a(x1)))) 37.82/10.59 A(a(b(b(x1)))) -> B(a(a(x1))) 37.82/10.59 B(a(a(b(x1)))) -> A(a(x1)) 37.82/10.59 A(a(b(b(x1)))) -> A(a(x1)) 37.82/10.59 A(a(b(b(x1)))) -> A(x1) 37.82/10.59 B(a(a(b(x1)))) -> A(x1) 37.82/10.59 37.82/10.59 The TRS R consists of the following rules: 37.82/10.59 37.82/10.59 b(b(a(a(x1)))) -> b(b(a(b(x1)))) 37.82/10.59 a(a(b(b(x1)))) -> b(b(a(a(x1))))
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