SRS_Standard 2019-03-29 03.29 pair #432294895

details

property	value
status	complete
benchmark	random-17.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n014.star.cs.uiowa.edu
space	Waldmann_19

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	7.84406 seconds
cpu usage	22.5151
user time	21.3057
system time	1.20942
max virtual memory	4.0695672E7
max residence set size	3390824.0

stage attributes

key	value
starexec-result	YES

output

21.36/6.37	YES
22.39/6.82	proof of /export/starexec/sandbox/benchmark/theBenchmark.xml
22.39/6.82	# AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty
22.39/6.82	
22.39/6.82	
22.39/6.82	Termination w.r.t. Q of the given QTRS could be proven:
22.39/6.82	
22.39/6.82	(0) QTRS
22.39/6.82	(1) FlatCCProof [EQUIVALENT, 0 ms]
22.39/6.82	(2) QTRS
22.39/6.82	(3) RootLabelingProof [EQUIVALENT, 0 ms]
22.39/6.82	(4) QTRS
22.39/6.82	(5) DependencyPairsProof [EQUIVALENT, 0 ms]
22.39/6.82	(6) QDP
22.39/6.82	(7) DependencyGraphProof [EQUIVALENT, 0 ms]
22.39/6.82	(8) QDP
22.39/6.82	(9) QDPOrderProof [EQUIVALENT, 172 ms]
22.39/6.82	(10) QDP
22.39/6.82	(11) PisEmptyProof [EQUIVALENT, 0 ms]
22.39/6.82	(12) YES
22.39/6.82	
22.39/6.82	
22.39/6.82	----------------------------------------
22.39/6.82	
22.39/6.82	(0)
22.39/6.82	Obligation:
22.39/6.82	Q restricted rewrite system:
22.39/6.82	The TRS R consists of the following rules:
22.39/6.82	
22.39/6.82	   a(a(b(b(x1)))) -> b(b(b(b(x1))))
22.39/6.82	   b(a(a(b(x1)))) -> b(b(b(b(x1))))
22.39/6.82	   a(a(b(b(x1)))) -> a(b(a(a(x1))))
22.39/6.82	
22.39/6.82	Q is empty.
22.39/6.82	
22.39/6.82	----------------------------------------
22.39/6.82	
22.39/6.82	(1) FlatCCProof (EQUIVALENT)
22.39/6.82	We used flat context closure [ROOTLAB]
22.39/6.82	As Q is empty the flat context closure was sound AND complete.
22.39/6.82	
22.39/6.82	----------------------------------------
22.39/6.82	
22.39/6.82	(2)
22.39/6.82	Obligation:
22.39/6.82	Q restricted rewrite system:
22.39/6.82	The TRS R consists of the following rules:
22.39/6.82	
22.39/6.82	   b(a(a(b(x1)))) -> b(b(b(b(x1))))
22.39/6.82	   a(a(b(b(x1)))) -> a(b(a(a(x1))))
22.39/6.82	   a(a(a(b(b(x1))))) -> a(b(b(b(b(x1)))))
22.39/6.82	   b(a(a(b(b(x1))))) -> b(b(b(b(b(x1)))))
22.39/6.82	
22.39/6.82	Q is empty.
22.39/6.82	
22.39/6.82	----------------------------------------
22.39/6.82	
22.39/6.82	(3) RootLabelingProof (EQUIVALENT)
22.39/6.82	We used plain root labeling [ROOTLAB] with the following heuristic:
22.39/6.82	LabelAll: All function symbols get labeled
22.39/6.82	
22.39/6.82	As Q is empty the root labeling was sound AND complete.
22.39/6.82	
22.39/6.82	----------------------------------------
22.39/6.82	
22.39/6.82	(4)
22.39/6.82	Obligation:
22.39/6.82	Q restricted rewrite system:
22.39/6.82	The TRS R consists of the following rules:
22.39/6.82	
22.39/6.82	   b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1))))
22.39/6.82	   b_{a_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))
22.39/6.82	   a_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1))))
22.39/6.82	   a_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1))))
22.39/6.82	   a_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))))
22.39/6.82	   a_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1)))))
22.39/6.82	   b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))))
22.39/6.82	   b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1)))))
22.39/6.82	
22.39/6.82	Q is empty.
22.39/6.82	
22.39/6.82	----------------------------------------
22.39/6.82	
22.39/6.82	(5) DependencyPairsProof (EQUIVALENT)
22.39/6.82	Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem.
22.39/6.82	----------------------------------------
22.39/6.82	
22.39/6.82	(6)
22.39/6.82	Obligation:
22.39/6.82	Q DP problem:
22.39/6.82	The TRS P consists of the following rules:
22.39/6.82	
22.39/6.82	   A_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{a_1}(a_{b_1}(x1)))
22.39/6.82	   A_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> A_{A_1}(a_{b_1}(x1))
22.39/6.82	   A_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{a_1}(a_{a_1}(x1)))
22.39/6.82	   A_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> A_{A_1}(a_{a_1}(x1))
22.39/6.82	   A_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> A_{A_1}(x1)
22.39/6.82	
22.39/6.82	The TRS R consists of the following rules:
22.39/6.82

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