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SRS_Standard 2019-03-29 03.29 pair #432295014
details
property
value
status
complete
benchmark
random-488.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n175.star.cs.uiowa.edu
space
Waldmann_19
run statistics
property
value
solver
ttt2-1.19
configuration
ttt2
runtime (wallclock)
1.88817 seconds
cpu usage
6.2264
user time
5.06619
system time
1.16021
max virtual memory
3551836.0
max residence set size
73956.0
stage attributes
key
value
starexec-result
YES
output
5.97/1.88 YES 5.97/1.88 5.97/1.88 Problem: 5.97/1.88 b(a(a(a(x1)))) -> a(b(b(b(x1)))) 5.97/1.88 b(a(a(a(x1)))) -> b(b(b(a(x1)))) 5.97/1.88 a(b(b(a(x1)))) -> a(a(a(a(x1)))) 5.97/1.88 5.97/1.88 Proof: 5.97/1.88 Matrix Interpretation Processor: dim=2 5.97/1.88 5.97/1.88 interpretation: 5.97/1.88 [1 0] [0] 5.97/1.88 [b](x0) = [0 0]x0 + [2], 5.97/1.88 5.97/1.88 [1 1] [1] 5.97/1.88 [a](x0) = [0 0]x0 + [0] 5.97/1.88 orientation: 5.97/1.88 [1 1] [3] [1 0] [3] 5.97/1.88 b(a(a(a(x1)))) = [0 0]x1 + [2] >= [0 0]x1 + [0] = a(b(b(b(x1)))) 5.97/1.88 5.97/1.88 [1 1] [3] [1 1] [1] 5.97/1.88 b(a(a(a(x1)))) = [0 0]x1 + [2] >= [0 0]x1 + [2] = b(b(b(a(x1)))) 5.97/1.88 5.97/1.88 [1 1] [4] [1 1] [4] 5.97/1.88 a(b(b(a(x1)))) = [0 0]x1 + [0] >= [0 0]x1 + [0] = a(a(a(a(x1)))) 5.97/1.88 problem: 5.97/1.88 b(a(a(a(x1)))) -> a(b(b(b(x1)))) 5.97/1.88 a(b(b(a(x1)))) -> a(a(a(a(x1)))) 5.97/1.88 KBO Processor: 5.97/1.88 weight function: 5.97/1.88 w0 = 1 5.97/1.88 w(b) = w(a) = 1 5.97/1.88 precedence: 5.97/1.88 b > a 5.97/1.88 problem: 5.97/1.88 5.97/1.88 Qed 5.97/1.88 EOF
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