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SRS_Standard 2019-03-29 03.29 pair #432295159
details
property
value
status
complete
benchmark
04.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n081.star.cs.uiowa.edu
space
Zantema_06
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
9.44927 seconds
cpu usage
33.1229
user time
31.8654
system time
1.25755
max virtual memory
4.1949796E7
max residence set size
4003420.0
stage attributes
key
value
starexec-result
YES
output
32.57/9.29 YES 32.57/9.30 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 32.57/9.30 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 32.57/9.30 32.57/9.30 32.57/9.30 Termination w.r.t. Q of the given QTRS could be proven: 32.57/9.30 32.57/9.30 (0) QTRS 32.57/9.30 (1) DependencyPairsProof [EQUIVALENT, 17 ms] 32.57/9.30 (2) QDP 32.57/9.30 (3) QDPOrderProof [EQUIVALENT, 34 ms] 32.57/9.30 (4) QDP 32.57/9.30 (5) QDPOrderProof [EQUIVALENT, 13 ms] 32.57/9.30 (6) QDP 32.57/9.30 (7) QDPOrderProof [EQUIVALENT, 29 ms] 32.57/9.30 (8) QDP 32.57/9.30 (9) DependencyGraphProof [EQUIVALENT, 0 ms] 32.57/9.30 (10) TRUE 32.57/9.30 32.57/9.30 32.57/9.30 ---------------------------------------- 32.57/9.30 32.57/9.30 (0) 32.57/9.30 Obligation: 32.57/9.30 Q restricted rewrite system: 32.57/9.30 The TRS R consists of the following rules: 32.57/9.30 32.57/9.30 a(a(b(x1))) -> b(a(x1)) 32.57/9.30 b(a(a(x1))) -> a(a(a(b(x1)))) 32.57/9.30 a(c(x1)) -> c(b(x1)) 32.57/9.30 32.57/9.30 Q is empty. 32.57/9.30 32.57/9.30 ---------------------------------------- 32.57/9.30 32.57/9.30 (1) DependencyPairsProof (EQUIVALENT) 32.57/9.30 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 32.57/9.30 ---------------------------------------- 32.57/9.30 32.57/9.30 (2) 32.57/9.30 Obligation: 32.57/9.30 Q DP problem: 32.57/9.30 The TRS P consists of the following rules: 32.57/9.30 32.57/9.30 A(a(b(x1))) -> B(a(x1)) 32.57/9.30 A(a(b(x1))) -> A(x1) 32.57/9.30 B(a(a(x1))) -> A(a(a(b(x1)))) 32.57/9.30 B(a(a(x1))) -> A(a(b(x1))) 32.57/9.30 B(a(a(x1))) -> A(b(x1)) 32.57/9.30 B(a(a(x1))) -> B(x1) 32.57/9.30 A(c(x1)) -> B(x1) 32.57/9.30 32.57/9.30 The TRS R consists of the following rules: 32.57/9.30 32.57/9.30 a(a(b(x1))) -> b(a(x1)) 32.57/9.30 b(a(a(x1))) -> a(a(a(b(x1)))) 32.57/9.30 a(c(x1)) -> c(b(x1)) 32.57/9.30 32.57/9.30 Q is empty. 32.57/9.30 We have to consider all minimal (P,Q,R)-chains. 32.57/9.30 ---------------------------------------- 32.57/9.30 32.57/9.30 (3) QDPOrderProof (EQUIVALENT) 32.57/9.30 We use the reduction pair processor [LPAR04,JAR06]. 32.57/9.30 32.57/9.30 32.57/9.30 The following pairs can be oriented strictly and are deleted. 32.57/9.30 32.57/9.30 A(c(x1)) -> B(x1) 32.57/9.30 The remaining pairs can at least be oriented weakly. 32.57/9.30 Used ordering: Polynomial interpretation [POLO]: 32.57/9.30 32.57/9.30 POL(A(x_1)) = x_1 32.57/9.30 POL(B(x_1)) = x_1 32.57/9.30 POL(a(x_1)) = x_1 32.57/9.30 POL(b(x_1)) = x_1 32.57/9.30 POL(c(x_1)) = 1 + x_1 32.57/9.30 32.57/9.30 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 32.57/9.30 32.57/9.30 b(a(a(x1))) -> a(a(a(b(x1)))) 32.57/9.30 a(a(b(x1))) -> b(a(x1)) 32.57/9.30 a(c(x1)) -> c(b(x1)) 32.57/9.30 32.57/9.30 32.57/9.30 ---------------------------------------- 32.57/9.30 32.57/9.30 (4) 32.57/9.30 Obligation: 32.57/9.30 Q DP problem: 32.57/9.30 The TRS P consists of the following rules: 32.57/9.30 32.57/9.30 A(a(b(x1))) -> B(a(x1)) 32.57/9.30 A(a(b(x1))) -> A(x1) 32.57/9.30 B(a(a(x1))) -> A(a(a(b(x1)))) 32.57/9.30 B(a(a(x1))) -> A(a(b(x1))) 32.57/9.30 B(a(a(x1))) -> A(b(x1)) 32.57/9.30 B(a(a(x1))) -> B(x1) 32.57/9.30 32.57/9.30 The TRS R consists of the following rules:
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