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Runtime_Complexity_Full_Rewriting 2019-04-01 06.11 pair #433307783
details
property
value
status
complete
benchmark
thiemann16.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n097.star.cs.uiowa.edu
space
AProVE_07
run statistics
property
value
solver
AProVE
configuration
complexity
runtime (wallclock)
291.508 seconds
cpu usage
317.929
user time
315.877
system time
2.05143
max virtual memory
1.82817E7
max residence set size
5423892.0
stage attributes
key
value
starexec-result
WORST_CASE(Omega(n^1), ?)
output
317.81/291.46 WORST_CASE(Omega(n^1), ?) 317.81/291.47 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 317.81/291.47 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 317.81/291.47 317.81/291.47 317.81/291.47 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). 317.81/291.47 317.81/291.47 (0) CpxTRS 317.81/291.47 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 317.81/291.47 (2) TRS for Loop Detection 317.81/291.47 (3) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] 317.81/291.47 (4) BEST 317.81/291.47 (5) proven lower bound 317.81/291.47 (6) LowerBoundPropagationProof [FINISHED, 0 ms] 317.81/291.47 (7) BOUNDS(n^1, INF) 317.81/291.47 (8) TRS for Loop Detection 317.81/291.47 317.81/291.47 317.81/291.47 ---------------------------------------- 317.81/291.47 317.81/291.47 (0) 317.81/291.47 Obligation: 317.81/291.47 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). 317.81/291.47 317.81/291.47 317.81/291.47 The TRS R consists of the following rules: 317.81/291.47 317.81/291.47 check(0) -> zero 317.81/291.47 check(s(0)) -> odd 317.81/291.47 check(s(s(0))) -> even 317.81/291.47 check(s(s(s(x)))) -> check(s(x)) 317.81/291.47 half(0) -> 0 317.81/291.47 half(s(0)) -> 0 317.81/291.47 half(s(s(x))) -> s(half(x)) 317.81/291.47 plus(0, y) -> y 317.81/291.47 plus(s(x), y) -> s(plus(x, y)) 317.81/291.47 times(x, y) -> timesIter(x, y, 0) 317.81/291.47 timesIter(x, y, z) -> if(check(x), x, y, z, plus(z, y)) 317.81/291.47 p(s(x)) -> x 317.81/291.47 p(0) -> 0 317.81/291.47 if(zero, x, y, z, u) -> z 317.81/291.47 if(odd, x, y, z, u) -> timesIter(p(x), y, u) 317.81/291.47 if(even, x, y, z, u) -> plus(timesIter(half(x), y, half(z)), timesIter(half(x), y, half(s(z)))) 317.81/291.47 317.81/291.47 S is empty. 317.81/291.47 Rewrite Strategy: FULL 317.81/291.47 ---------------------------------------- 317.81/291.47 317.81/291.47 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 317.81/291.47 Transformed a relative TRS into a decreasing-loop problem. 317.81/291.47 ---------------------------------------- 317.81/291.47 317.81/291.47 (2) 317.81/291.47 Obligation: 317.81/291.47 Analyzing the following TRS for decreasing loops: 317.81/291.47 317.81/291.47 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(n^1, INF). 317.81/291.47 317.81/291.47 317.81/291.47 The TRS R consists of the following rules: 317.81/291.47 317.81/291.47 check(0) -> zero 317.81/291.47 check(s(0)) -> odd 317.81/291.47 check(s(s(0))) -> even 317.81/291.47 check(s(s(s(x)))) -> check(s(x)) 317.81/291.47 half(0) -> 0 317.81/291.47 half(s(0)) -> 0 317.81/291.47 half(s(s(x))) -> s(half(x)) 317.81/291.47 plus(0, y) -> y 317.81/291.47 plus(s(x), y) -> s(plus(x, y)) 317.81/291.47 times(x, y) -> timesIter(x, y, 0) 317.81/291.47 timesIter(x, y, z) -> if(check(x), x, y, z, plus(z, y)) 317.81/291.47 p(s(x)) -> x 317.81/291.47 p(0) -> 0 317.81/291.47 if(zero, x, y, z, u) -> z 317.81/291.47 if(odd, x, y, z, u) -> timesIter(p(x), y, u) 317.81/291.47 if(even, x, y, z, u) -> plus(timesIter(half(x), y, half(z)), timesIter(half(x), y, half(s(z)))) 317.81/291.47 317.81/291.47 S is empty. 317.81/291.47 Rewrite Strategy: FULL 317.81/291.47 ---------------------------------------- 317.81/291.47 317.81/291.47 (3) DecreasingLoopProof (LOWER BOUND(ID)) 317.81/291.47 The following loop(s) give(s) rise to the lower bound Omega(n^1): 317.81/291.47 317.81/291.47 The rewrite sequence 317.81/291.47 317.81/291.47 check(s(s(s(x)))) ->^+ check(s(x)) 317.81/291.47 317.81/291.47 gives rise to a decreasing loop by considering the right hand sides subterm at position []. 317.81/291.47 317.81/291.47 The pumping substitution is [x / s(s(x))]. 317.81/291.47 317.81/291.47 The result substitution is [ ]. 317.81/291.47 317.81/291.47 317.81/291.47 317.81/291.47 317.81/291.47 ---------------------------------------- 317.81/291.47
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