details

property	value
status	complete
benchmark	PEANO_nosorts-noand_L.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n118.star.cs.uiowa.edu
space	Strategy_outermost_added_08

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.26305 seconds
cpu usage	2.60404
user time	2.49615
system time	0.107893
max virtual memory	1.8275288E7
max residence set size	183864.0

stage attributes

key	value
starexec-result	NO

output

2.50/1.23 NO 2.50/1.23 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 2.50/1.23 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.50/1.23 2.50/1.23 2.50/1.23 Outermost Termination of the given OTRS could be disproven: 2.50/1.23 2.50/1.23 (0) OTRS 2.50/1.23 (1) OutermostNonTerminationProof [COMPLETE, 0 ms] 2.50/1.23 (2) NO 2.50/1.23 2.50/1.23 2.50/1.23 ---------------------------------------- 2.50/1.23 2.50/1.23 (0) 2.50/1.23 Obligation: 2.50/1.23 Term rewrite system R: 2.50/1.23 The TRS R consists of the following rules: 2.50/1.23 2.50/1.23 U12(tt) -> s(plus(N, M)) 2.50/1.23 U11(tt) -> U12(tt) 2.50/1.23 plus(N, 0) -> N 2.50/1.23 plus(N, s(M)) -> U11(tt) 2.50/1.23 2.50/1.23 2.50/1.23 2.50/1.23 Outermost Strategy. 2.50/1.23 2.50/1.23 ---------------------------------------- 2.50/1.23 2.50/1.23 (1) OutermostNonTerminationProof (COMPLETE) 2.50/1.23 Term rewrite system R: 2.50/1.23 The TRS R consists of the following rules: 2.50/1.23 2.50/1.23 U12(tt) -> s(plus(N, M)) 2.50/1.23 U11(tt) -> U12(tt) 2.50/1.23 plus(N, 0) -> N 2.50/1.23 plus(N, s(M)) -> U11(tt) 2.50/1.23 2.50/1.23 2.50/1.23 2.50/1.23 Outermost Strategy. 2.50/1.23 2.50/1.23 ---------- Loop: ---------- 2.50/1.23 2.50/1.23 plus(N, U12(tt)) -> plus(N, s(plus(U12(tt), U12(tt)))) with rule U12(tt) -> s(plus(N, M)) at position [1] and matcher [N / U12(tt), M / U12(tt)] 2.50/1.23 2.50/1.23 plus(N, s(plus(U12(tt), U12(tt)))) -> U11(tt) with rule plus(N', s(M)) -> U11(tt) at position [] and matcher [N' / N, M / plus(U12(tt), U12(tt))] 2.58/1.23 2.58/1.23 U11(tt) -> U12(tt) with rule U11(tt) -> U12(tt) at position [] and matcher [ ] 2.58/1.23 2.58/1.23 U12(tt) -> s(plus(U12(tt), U12(tt))) with rule U12(tt) -> s(plus(N, M)) at position [] and matcher [N / U12(tt), M / U12(tt)] 2.58/1.23 2.58/1.23 Now an instance of the first term with Matcher [N / U12(tt)] occurs in the last term at position [0]. 2.58/1.23 2.58/1.23 Context: s([]) 2.58/1.23 2.58/1.23 We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. 2.58/1.23 ---------------------------------------- 2.58/1.23 2.58/1.23 (2) 2.58/1.23 NO 2.58/1.26 EOF popout

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all output return to TRS_Outermost 2019-04-01 06.45