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TRS_Outermost 2019-04-01 06.45 pair #433314714
details
property
value
status
complete
benchmark
Ex5_7_Luc97.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n133.star.cs.uiowa.edu
space
Strategy_outermost_added_08
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.40699 seconds
cpu usage
2.99703
user time
2.84564
system time
0.151391
max virtual memory
1.8275288E7
max residence set size
208820.0
stage attributes
key
value
starexec-result
NO
output
2.76/1.36 NO 2.97/1.37 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 2.97/1.37 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.97/1.37 2.97/1.37 2.97/1.37 Outermost Termination of the given OTRS could be disproven: 2.97/1.37 2.97/1.37 (0) OTRS 2.97/1.37 (1) OutermostNonTerminationProof [COMPLETE, 0 ms] 2.97/1.37 (2) NO 2.97/1.37 2.97/1.37 2.97/1.37 ---------------------------------------- 2.97/1.37 2.97/1.37 (0) 2.97/1.37 Obligation: 2.97/1.37 Term rewrite system R: 2.97/1.37 The TRS R consists of the following rules: 2.97/1.37 2.97/1.37 dbl(0) -> 0 2.97/1.37 dbl(s(X)) -> s(s(dbl(X))) 2.97/1.37 dbls(nil) -> nil 2.97/1.37 dbls(cons(X, Y)) -> cons(dbl(X), dbls(Y)) 2.97/1.37 sel(0, cons(X, Y)) -> X 2.97/1.37 sel(s(X), cons(Y, Z)) -> sel(X, Z) 2.97/1.37 indx(nil, X) -> nil 2.97/1.37 indx(cons(X, Y), Z) -> cons(sel(X, Z), indx(Y, Z)) 2.97/1.37 from(X) -> cons(X, from(s(X))) 2.97/1.37 dbl1(0) -> 01 2.97/1.37 dbl1(s(X)) -> s1(s1(dbl1(X))) 2.97/1.37 sel1(0, cons(X, Y)) -> X 2.97/1.37 sel1(s(X), cons(Y, Z)) -> sel1(X, Z) 2.97/1.37 quote(0) -> 01 2.97/1.37 quote(s(X)) -> s1(quote(X)) 2.97/1.37 quote(dbl(X)) -> dbl1(X) 2.97/1.37 quote(sel(X, Y)) -> sel1(X, Y) 2.97/1.37 2.97/1.37 2.97/1.37 2.97/1.37 Outermost Strategy. 2.97/1.37 2.97/1.37 ---------------------------------------- 2.97/1.37 2.97/1.37 (1) OutermostNonTerminationProof (COMPLETE) 2.97/1.37 Term rewrite system R: 2.97/1.37 The TRS R consists of the following rules: 2.97/1.37 2.97/1.37 dbl(0) -> 0 2.97/1.37 dbl(s(X)) -> s(s(dbl(X))) 2.97/1.37 dbls(nil) -> nil 2.97/1.37 dbls(cons(X, Y)) -> cons(dbl(X), dbls(Y)) 2.97/1.37 sel(0, cons(X, Y)) -> X 2.97/1.37 sel(s(X), cons(Y, Z)) -> sel(X, Z) 2.97/1.37 indx(nil, X) -> nil 2.97/1.37 indx(cons(X, Y), Z) -> cons(sel(X, Z), indx(Y, Z)) 2.97/1.37 from(X) -> cons(X, from(s(X))) 2.97/1.37 dbl1(0) -> 01 2.97/1.37 dbl1(s(X)) -> s1(s1(dbl1(X))) 2.97/1.37 sel1(0, cons(X, Y)) -> X 2.97/1.37 sel1(s(X), cons(Y, Z)) -> sel1(X, Z) 2.97/1.37 quote(0) -> 01 2.97/1.37 quote(s(X)) -> s1(quote(X)) 2.97/1.37 quote(dbl(X)) -> dbl1(X) 2.97/1.37 quote(sel(X, Y)) -> sel1(X, Y) 2.97/1.37 2.97/1.37 2.97/1.37 2.97/1.37 Outermost Strategy. 2.97/1.37 2.97/1.37 ---------- Loop: ---------- 2.97/1.37 2.97/1.37 from(X) -> cons(X, from(s(X))) with rule from(X') -> cons(X', from(s(X'))) at position [] and matcher [X' / X] 2.97/1.37 2.97/1.37 Now an instance of the first term with Matcher [X / s(X)] occurs in the last term at position [1]. 2.97/1.37 2.97/1.37 Context: cons(X, []) 2.97/1.37 2.97/1.37 We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. 2.97/1.37 ---------------------------------------- 2.97/1.37 2.97/1.37 (2) 2.97/1.37 NO 2.97/1.40 EOF
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