details

property	value
status	complete
benchmark	#4.2.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n133.star.cs.uiowa.edu
space	Strategy_outermost_added_08

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.22867 seconds
cpu usage	2.75806
user time	2.6153
system time	0.142762
max virtual memory	1.8275288E7
max residence set size	201672.0

stage attributes

key	value
starexec-result	NO

output

2.58/1.19 NO 2.58/1.19 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 2.58/1.19 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.58/1.19 2.58/1.19 2.58/1.19 Outermost Termination of the given OTRS could be disproven: 2.58/1.19 2.58/1.19 (0) OTRS 2.58/1.19 (1) OutermostNonTerminationProof [COMPLETE, 0 ms] 2.58/1.19 (2) NO 2.58/1.19 2.58/1.19 2.58/1.19 ---------------------------------------- 2.58/1.19 2.58/1.19 (0) 2.58/1.19 Obligation: 2.58/1.19 Term rewrite system R: 2.58/1.19 The TRS R consists of the following rules: 2.58/1.19 2.58/1.19 f(g(x), s(0), y) -> f(y, y, g(x)) 2.58/1.19 g(s(x)) -> s(g(x)) 2.58/1.19 g(0) -> 0 2.58/1.19 2.58/1.19 2.58/1.19 2.58/1.19 Outermost Strategy. 2.58/1.19 2.58/1.19 ---------------------------------------- 2.58/1.19 2.58/1.19 (1) OutermostNonTerminationProof (COMPLETE) 2.58/1.19 Term rewrite system R: 2.58/1.19 The TRS R consists of the following rules: 2.58/1.19 2.58/1.19 f(g(x), s(0), y) -> f(y, y, g(x)) 2.58/1.19 g(s(x)) -> s(g(x)) 2.58/1.19 g(0) -> 0 2.58/1.19 2.58/1.19 2.58/1.19 2.58/1.19 Outermost Strategy. 2.58/1.19 2.58/1.19 ---------- Loop: ---------- 2.58/1.19 2.58/1.19 f(g(s(0)), g(s(0)), g(s(0))) -> f(g(s(0)), s(g(0)), g(s(0))) with rule g(s(x')) -> s(g(x')) at position [1] and matcher [x' / 0] 2.58/1.19 2.58/1.19 f(g(s(0)), s(g(0)), g(s(0))) -> f(g(s(0)), s(0), g(s(0))) with rule g(0) -> 0 at position [1,0] and matcher [ ] 2.58/1.19 2.58/1.19 f(g(s(0)), s(0), g(s(0))) -> f(g(s(0)), g(s(0)), g(s(0))) with rule f(g(x), s(0), y) -> f(y, y, g(x)) at position [] and matcher [x / s(0), y / g(s(0))] 2.58/1.19 2.58/1.19 Now an instance of the first term with Matcher [ ] occurs in the last term at position []. 2.58/1.19 2.58/1.19 Context: [] 2.58/1.19 2.58/1.19 We used [THIEMANN_LOOPS_UNDER_STRATEGIES] to show that this Loop is an Outermost-Loop. 2.58/1.19 ---------------------------------------- 2.58/1.19 2.58/1.19 (2) 2.58/1.19 NO 2.75/1.22 EOF popout

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job log

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actions

all output return to TRS_Outermost 2019-04-01 06.45