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TRS_Outermost 2019-04-01 06.45 pair #433314834
details
property
value
status
complete
benchmark
ex8.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n092.star.cs.uiowa.edu
space
Zantema_08
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.42628 seconds
cpu usage
6.19449
user time
5.96081
system time
0.233678
max virtual memory
3.6569888E7
max residence set size
592916.0
stage attributes
key
value
starexec-result
YES
output
5.82/2.23 YES 5.82/2.24 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 5.82/2.24 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 5.82/2.24 5.82/2.24 5.82/2.24 Outermost Termination of the given OTRS could be proven: 5.82/2.24 5.82/2.24 (0) OTRS 5.82/2.24 (1) Thiemann-SpecialC-Transformation [EQUIVALENT, 0 ms] 5.82/2.24 (2) QTRS 5.82/2.24 (3) DependencyPairsProof [EQUIVALENT, 0 ms] 5.82/2.24 (4) QDP 5.82/2.24 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 5.82/2.24 (6) QDP 5.82/2.24 (7) UsableRulesProof [EQUIVALENT, 0 ms] 5.82/2.24 (8) QDP 5.82/2.24 (9) QReductionProof [EQUIVALENT, 0 ms] 5.82/2.24 (10) QDP 5.82/2.24 (11) RFCMatchBoundsDPProof [EQUIVALENT, 16 ms] 5.82/2.24 (12) YES 5.82/2.24 5.82/2.24 5.82/2.24 ---------------------------------------- 5.82/2.24 5.82/2.24 (0) 5.82/2.24 Obligation: 5.82/2.24 Term rewrite system R: 5.82/2.24 The TRS R consists of the following rules: 5.82/2.24 5.82/2.24 f(g(x)) -> g(g(x)) 5.82/2.24 g(x) -> f(f(x)) 5.82/2.24 f(f(x)) -> x 5.82/2.24 5.82/2.24 5.82/2.24 5.82/2.24 Outermost Strategy. 5.82/2.24 5.82/2.24 ---------------------------------------- 5.82/2.24 5.82/2.24 (1) Thiemann-SpecialC-Transformation (EQUIVALENT) 5.82/2.24 We applied the Thiemann-SpecialC transformation to transform the outermost TRS to an innermost TRS. 5.82/2.24 ---------------------------------------- 5.82/2.24 5.82/2.24 (2) 5.82/2.24 Obligation: 5.82/2.24 Q restricted rewrite system: 5.82/2.24 The TRS R consists of the following rules: 5.82/2.24 5.82/2.24 top(go_up(x)) -> top(reduce(x)) 5.82/2.24 reduce(f(x_1)) -> check_f(redex_f(x_1)) 5.82/2.24 reduce(g(x_1)) -> check_g(redex_g(x_1)) 5.82/2.24 redex_f(g(x)) -> result_f(g(g(x))) 5.82/2.24 redex_g(x) -> result_g(f(f(x))) 5.82/2.24 redex_f(f(x)) -> result_f(x) 5.82/2.24 check_f(result_f(x)) -> go_up(x) 5.82/2.24 check_g(result_g(x)) -> go_up(x) 5.82/2.24 check_f(redex_f(x_1)) -> in_f_1(reduce(x_1)) 5.82/2.24 check_g(redex_g(x_1)) -> in_g_1(reduce(x_1)) 5.82/2.24 in_f_1(go_up(x_1)) -> go_up(f(x_1)) 5.82/2.24 in_g_1(go_up(x_1)) -> go_up(g(x_1)) 5.82/2.24 5.82/2.24 The set Q consists of the following terms: 5.82/2.24 5.82/2.24 top(go_up(x0)) 5.82/2.24 reduce(f(x0)) 5.82/2.24 reduce(g(x0)) 5.82/2.24 redex_f(g(x0)) 5.82/2.24 redex_g(x0) 5.82/2.24 redex_f(f(x0)) 5.82/2.24 check_f(result_f(x0)) 5.82/2.24 check_g(result_g(x0)) 5.82/2.24 check_f(redex_f(x0)) 5.82/2.24 in_f_1(go_up(x0)) 5.82/2.24 in_g_1(go_up(x0)) 5.82/2.24 5.82/2.24 5.82/2.24 ---------------------------------------- 5.82/2.24 5.82/2.24 (3) DependencyPairsProof (EQUIVALENT) 5.82/2.24 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 5.82/2.24 ---------------------------------------- 5.82/2.24 5.82/2.24 (4) 5.82/2.24 Obligation: 5.82/2.24 Q DP problem: 5.82/2.24 The TRS P consists of the following rules: 5.82/2.24 5.82/2.24 TOP(go_up(x)) -> TOP(reduce(x)) 5.82/2.24 TOP(go_up(x)) -> REDUCE(x) 5.82/2.24 REDUCE(f(x_1)) -> CHECK_F(redex_f(x_1)) 5.82/2.24 REDUCE(f(x_1)) -> REDEX_F(x_1) 5.82/2.24 REDUCE(g(x_1)) -> CHECK_G(redex_g(x_1)) 5.82/2.24 REDUCE(g(x_1)) -> REDEX_G(x_1) 5.82/2.24 CHECK_F(redex_f(x_1)) -> IN_F_1(reduce(x_1)) 5.82/2.24 CHECK_F(redex_f(x_1)) -> REDUCE(x_1) 5.82/2.24 CHECK_G(redex_g(x_1)) -> IN_G_1(reduce(x_1)) 5.82/2.24 CHECK_G(redex_g(x_1)) -> REDUCE(x_1) 5.82/2.24 5.82/2.24 The TRS R consists of the following rules: 5.82/2.24
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