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Java_Bytecode 2019-04-01 06.50 pair #433315528
details
property
value
status
complete
benchmark
NO_21.jar
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n155.star.cs.uiowa.edu
space
Julia_11_iterative
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.0672 seconds
cpu usage
4.3141
user time
4.12224
system time
0.19186
max virtual memory
1.8478228E7
max residence set size
336468.0
stage attributes
key
value
starexec-result
NO
output
4.25/2.03 NO 4.25/2.03 proof of /export/starexec/sandbox/benchmark/theBenchmark.jar 4.25/2.03 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.25/2.03 4.25/2.03 4.25/2.03 termination of the given Bare JBC problem could be disproven: 4.25/2.03 4.25/2.03 (0) Bare JBC problem 4.25/2.03 (1) BareJBCToJBCProof [EQUIVALENT, 96 ms] 4.25/2.03 (2) JBC problem 4.25/2.03 (3) JBCNonTerm [COMPLETE, 161 ms] 4.25/2.03 (4) NO 4.25/2.03 4.25/2.03 4.25/2.03 ---------------------------------------- 4.25/2.03 4.25/2.03 (0) 4.25/2.03 Obligation: 4.25/2.03 need to prove termination of the following program: 4.25/2.03 public class NO_21 { 4.25/2.03 public static void main(String args[]) { 4.25/2.03 int i = 0; 4.25/2.03 while (i < 100) { 4.25/2.03 i++; 4.25/2.03 i--; 4.25/2.03 } 4.25/2.03 } 4.25/2.03 } 4.25/2.03 4.25/2.03 4.25/2.03 4.25/2.03 ---------------------------------------- 4.25/2.03 4.25/2.03 (1) BareJBCToJBCProof (EQUIVALENT) 4.25/2.03 initialized classpath 4.25/2.03 ---------------------------------------- 4.25/2.03 4.25/2.03 (2) 4.25/2.03 Obligation: 4.25/2.03 need to prove termination of the following program: 4.25/2.03 public class NO_21 { 4.25/2.03 public static void main(String args[]) { 4.25/2.03 int i = 0; 4.25/2.03 while (i < 100) { 4.25/2.03 i++; 4.25/2.03 i--; 4.25/2.03 } 4.25/2.03 } 4.25/2.03 } 4.25/2.03 4.25/2.03 4.25/2.03 4.25/2.03 ---------------------------------------- 4.25/2.03 4.25/2.03 (3) JBCNonTerm (COMPLETE) 4.25/2.03 Constructed a run with a repetition. States 2 and 8 are repetitions (when considering only the interesting positions []). 4.25/2.03 4.25/2.03 0:<NO_21.main||0: push 0|| - || -> 4.25/2.03 YES: (JL1) 4.25/2.03 1:<NO_21.main||1: store INT to #1|| - ||0> 4.25/2.03 YES: (JL1) 4.25/2.03 2:<NO_21.main||2: load INT #1||#1: 0|| -> 4.25/2.03 YES: (JL1) 4.25/2.03 3:<NO_21.main||3: push 100||#1: 0||0> 4.25/2.03 YES: (JL1) 4.25/2.03 4:<NO_21.main||5: GE||#1: 0||0, 100> 4.25/2.03 YES: (JL1) 4.25/2.03 5:<NO_21.main||8: increment #1 by 1||#1: 0|| -> 4.25/2.03 YES: (JL1) 4.25/2.03 6:<NO_21.main||11: increment #1 by -1||#1: 1|| -> 4.25/2.03 YES: (JL1) 4.25/2.03 7:<NO_21.main||14: jmp||#1: 0|| -> 4.25/2.03 YES: (JL1) 4.25/2.03 8:<NO_21.main||2: load INT #1||#1: 0|| -> 4.25/2.03 YES: (JL1) 4.25/2.03 4.25/2.03 ---------------------------------------- 4.25/2.03 4.25/2.03 (4) 4.25/2.03 NO 4.29/2.06 EOF
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