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Logic_Programming 2019-04-02 08.22 pair #434324499
details
property
value
status
complete
benchmark
reminder.pl
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n178.star.cs.uiowa.edu
space
talp_talp
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
2.77803 seconds
cpu usage
7.19276
user time
6.81454
system time
0.378223
max virtual memory
1.960924E7
max residence set size
600004.0
stage attributes
key
value
starexec-result
YES
output
6.68/2.70 YES 6.97/2.73 proof of /export/starexec/sandbox/benchmark/theBenchmark.pl 6.97/2.73 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 6.97/2.73 6.97/2.73 6.97/2.73 Left Termination of the query pattern 6.97/2.73 6.97/2.73 rem(g,g,a) 6.97/2.73 6.97/2.73 w.r.t. the given Prolog program could successfully be proven: 6.97/2.73 6.97/2.73 (0) Prolog 6.97/2.73 (1) PrologToDTProblemTransformerProof [SOUND, 44 ms] 6.97/2.73 (2) TRIPLES 6.97/2.73 (3) TriplesToPiDPProof [SOUND, 0 ms] 6.97/2.73 (4) PiDP 6.97/2.73 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 6.97/2.73 (6) AND 6.97/2.73 (7) PiDP 6.97/2.73 (8) UsableRulesProof [EQUIVALENT, 0 ms] 6.97/2.73 (9) PiDP 6.97/2.73 (10) PiDPToQDPProof [EQUIVALENT, 0 ms] 6.97/2.73 (11) QDP 6.97/2.73 (12) QDPSizeChangeProof [EQUIVALENT, 0 ms] 6.97/2.73 (13) YES 6.97/2.73 (14) PiDP 6.97/2.73 (15) UsableRulesProof [EQUIVALENT, 0 ms] 6.97/2.73 (16) PiDP 6.97/2.73 (17) PiDPToQDPProof [SOUND, 0 ms] 6.97/2.73 (18) QDP 6.97/2.73 (19) QDPSizeChangeProof [EQUIVALENT, 0 ms] 6.97/2.73 (20) YES 6.97/2.73 (21) PiDP 6.97/2.73 (22) PiDPToQDPProof [SOUND, 0 ms] 6.97/2.73 (23) QDP 6.97/2.73 (24) QDPOrderProof [EQUIVALENT, 33 ms] 6.97/2.73 (25) QDP 6.97/2.73 (26) PisEmptyProof [EQUIVALENT, 0 ms] 6.97/2.73 (27) YES 6.97/2.73 6.97/2.73 6.97/2.73 ---------------------------------------- 6.97/2.73 6.97/2.73 (0) 6.97/2.73 Obligation: 6.97/2.73 Clauses: 6.97/2.73 6.97/2.73 rem(X, Y, R) :- ','(notZero(Y), ','(sub(X, Y, Z), rem(Z, Y, R))). 6.97/2.73 rem(X, Y, X) :- ','(notZero(Y), geq(X, Y)). 6.97/2.73 sub(s(X), s(Y), Z) :- sub(X, Y, Z). 6.97/2.73 sub(X, 0, X). 6.97/2.73 notZero(s(X)). 6.97/2.73 geq(s(X), s(Y)) :- geq(X, Y). 6.97/2.73 geq(X, 0). 6.97/2.73 6.97/2.73 6.97/2.73 Query: rem(g,g,a) 6.97/2.73 ---------------------------------------- 6.97/2.73 6.97/2.73 (1) PrologToDTProblemTransformerProof (SOUND) 6.97/2.73 Built DT problem from termination graph DT10. 6.97/2.73 6.97/2.73 { 6.97/2.73 "root": 16, 6.97/2.73 "program": { 6.97/2.73 "directives": [], 6.97/2.73 "clauses": [ 6.97/2.73 [ 6.97/2.73 "(rem X Y R)", 6.97/2.73 "(',' (notZero Y) (',' (sub X Y Z) (rem Z Y R)))" 6.97/2.73 ], 6.97/2.73 [ 6.97/2.73 "(rem X Y X)", 6.97/2.73 "(',' (notZero Y) (geq X Y))" 6.97/2.73 ], 6.97/2.73 [ 6.97/2.73 "(sub (s X) (s Y) Z)", 6.97/2.73 "(sub X Y Z)" 6.97/2.73 ], 6.97/2.73 [ 6.97/2.73 "(sub X (0) X)", 6.97/2.73 null 6.97/2.73 ], 6.97/2.73 [ 6.97/2.73 "(notZero (s X))", 6.97/2.73 null 6.97/2.73 ], 6.97/2.73 [ 6.97/2.73 "(geq (s X) (s Y))", 6.97/2.73 "(geq X Y)" 6.97/2.73 ], 6.97/2.73 [ 6.97/2.73 "(geq X (0))", 6.97/2.73 null 6.97/2.73 ] 6.97/2.73 ] 6.97/2.73 }, 6.97/2.73 "graph": { 6.97/2.73 "nodes": { 6.97/2.73 "type": "Nodes",
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