details

property	value
status	complete
benchmark	#4.32.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n183.star.cs.uiowa.edu
space	Strategy_removed_AG01

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.464109 seconds
cpu usage	0.790279
user time	0.615821
system time	0.174458
max virtual memory	96176.0
max residence set size	60412.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: f(x,c(y)) -> f(x,s(f(y,y))) f(s(x),s(y)) -> f(x,s(c(s(y)))) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1 1 0] [f](x0, x1) = [1 0 0]x0 + [0 1 0]x1 [0 0 0] [0 0 0] , [1 0 0] [0] [c](x0) = [1 1 1]x0 + [1] [0 0 0] [0], [1 0 0] [s](x0) = [0 0 0]x0 [1 1 0] orientation: [1 0 0] [2 1 1] [1] [1 0 0] [2 1 0] f(x,c(y)) = [1 0 0]x + [1 1 1]y + [1] >= [1 0 0]x + [0 0 0]y = f(x,s(f(y,y))) [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [1 0 0] [1 0 0] [1 0 0] [1 0 0] f(s(x),s(y)) = [1 0 0]x + [0 0 0]y >= [1 0 0]x + [0 0 0]y = f(x,s(c(s(y)))) [0 0 0] [0 0 0] [0 0 0] [0 0 0] problem: f(s(x),s(y)) -> f(x,s(c(s(y)))) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [1 0 0] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [1 0 0] [c](x0) = [0 0 0]x0 [0 0 0] , [1 0 0] [0] [s](x0) = [0 0 0]x0 + [0] [0 0 1] [1] orientation: [1 0 1] [1 0 0] [1] [1 0 1] [1 0 0] f(s(x),s(y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y = f(x,s(c(s(y)))) [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] problem: Qed popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Standard