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TRS Standard pair #487066972
details
property
value
status
complete
benchmark
#4.22.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n173.star.cs.uiowa.edu
space
Strategy_removed_AG01
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.436488 seconds
cpu usage
0.709217
user time
0.514159
system time
0.195058
max virtual memory
96176.0
max residence set size
60316.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) Proof: DP Processor: DPs: quot#(s(x),s(y),z) -> quot#(x,y,z) quot#(x,0(),s(z)) -> quot#(x,s(z),s(z)) TRS: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) Subterm Criterion Processor: simple projection: pi(quot#) = 0 problem: DPs: quot#(x,0(),s(z)) -> quot#(x,s(z),s(z)) TRS: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) EDG Processor: DPs: quot#(x,0(),s(z)) -> quot#(x,s(z),s(z)) TRS: quot(0(),s(y),s(z)) -> 0() quot(s(x),s(y),z) -> quot(x,y,z) quot(x,0(),s(z)) -> s(quot(x,s(z),s(z))) graph: SCC Processor: #sccs: 0 #rules: 0 #arcs: 0/1
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