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TRS Standard pair #487067127
details
property
value
status
complete
benchmark
pair3rotate.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n187.star.cs.uiowa.edu
space
Endrullis_06
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
2.25954 seconds
cpu usage
7.3573
user time
6.04875
system time
1.30855
max virtual memory
5680596.0
max residence set size
97632.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: p(a(x0),p(b(x1),p(a(x2),x3))) -> p(x2,p(a(a(x0)),p(b(x1),x3))) Proof: DP Processor: DPs: p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(b(x1),x3) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) TRS: p(a(x0),p(b(x1),p(a(x2),x3))) -> p(x2,p(a(a(x0)),p(b(x1),x3))) EDG Processor: DPs: p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(b(x1),x3) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) TRS: p(a(x0),p(b(x1),p(a(x2),x3))) -> p(x2,p(a(a(x0)),p(b(x1),x3))) graph: p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) -> p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(b(x1),x3) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) -> p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) -> p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) -> p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(b(x1),x3) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) -> p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) -> p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) SCC Processor: #sccs: 1 #rules: 2 #arcs: 6/9 DPs: p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(a(a(x0)),p(b(x1),x3)) p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) TRS: p(a(x0),p(b(x1),p(a(x2),x3))) -> p(x2,p(a(a(x0)),p(b(x1),x3))) Subterm Criterion Processor: simple projection: pi(p) = [1,1] pi(p#) = [1,1] problem: DPs: p#(a(x0),p(b(x1),p(a(x2),x3))) -> p#(x2,p(a(a(x0)),p(b(x1),x3))) TRS: p(a(x0),p(b(x1),p(a(x2),x3))) -> p(x2,p(a(a(x0)),p(b(x1),x3))) Semantic Labeling Processor: dimension: 2 usable rules: interpretation: [0] [b](x0) = [1], [1 1] [a](x0) = [0 0]x0, [1 1] [0 1] [1] [p](x0, x1) = [1 0]x0 + [0 1]x1 + [0] labeled: p# usable (for model): p# a p b argument filtering: pi(a) = 0 pi(b) = [] pi(p) = 0 pi(p#) = [] precedence: p# ~ p ~ b ~ a problem: DPs: TRS: p(a(x0),p(b(x1),p(a(x2),x3))) -> p(x2,p(a(a(x0)),p(b(x1),x3))) Qed
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