Spaces
Explore
Communities
Statistics
Reports
Cluster
Status
Help
TRS Standard pair #487067138
details
property
value
status
complete
benchmark
pair2simple2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n191.star.cs.uiowa.edu
space
Endrullis_06
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
1.88323 seconds
cpu usage
4.40547
user time
4.21454
system time
0.190933
max virtual memory
1.8477524E7
max residence set size
268520.0
stage attributes
key
value
starexec-result
YES
output
YES proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) DependencyPairsProof [EQUIVALENT, 0 ms] (2) QDP (3) QDPOrderProof [EQUIVALENT, 0 ms] (4) QDP (5) QDPOrderProof [EQUIVALENT, 17 ms] (6) QDP (7) PisEmptyProof [EQUIVALENT, 0 ms] (8) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: p(a(x0), p(a(a(a(x1))), x2)) -> p(a(x2), p(a(a(b(x0))), x2)) Q is empty. ---------------------------------------- (1) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (2) Obligation: Q DP problem: The TRS P consists of the following rules: P(a(x0), p(a(a(a(x1))), x2)) -> P(a(x2), p(a(a(b(x0))), x2)) P(a(x0), p(a(a(a(x1))), x2)) -> P(a(a(b(x0))), x2) The TRS R consists of the following rules: p(a(x0), p(a(a(a(x1))), x2)) -> p(a(x2), p(a(a(b(x0))), x2)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (3) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted. P(a(x0), p(a(a(a(x1))), x2)) -> P(a(a(b(x0))), x2) The remaining pairs can at least be oriented weakly. Used ordering: Combined order from the following AFS and order. P(x1, x2) = x2 p(x1, x2) = p(x2) Knuth-Bendix order [KBO] with precedence:trivial and weight map: dummyConstant=1 p_1=1 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: p(a(x0), p(a(a(a(x1))), x2)) -> p(a(x2), p(a(a(b(x0))), x2)) ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: P(a(x0), p(a(a(a(x1))), x2)) -> P(a(x2), p(a(a(b(x0))), x2)) The TRS R consists of the following rules: p(a(x0), p(a(a(a(x1))), x2)) -> p(a(x2), p(a(a(b(x0))), x2)) Q is empty. We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) QDPOrderProof (EQUIVALENT) We use the reduction pair processor [LPAR04,JAR06]. The following pairs can be oriented strictly and are deleted.
popout
output may be truncated. 'popout' for the full output.
job log
popout
actions
all output
return to TRS Standard