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TRS Standard pair #487067188
details
property
value
status
complete
benchmark
enger-nonloop-swapXY.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n177.star.cs.uiowa.edu
space
EEG_IJCAR_12
run statistics
property
value
solver
AProVE
configuration
standard
runtime (wallclock)
12.1239 seconds
cpu usage
37.845
user time
36.4865
system time
1.35859
max virtual memory
1.8719788E7
max residence set size
3978840.0
stage attributes
key
value
starexec-result
NO
output
NO proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) AAECC Innermost [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) QDP (5) DependencyGraphProof [EQUIVALENT, 0 ms] (6) AND (7) QDP (8) UsableRulesProof [EQUIVALENT, 0 ms] (9) QDP (10) QReductionProof [EQUIVALENT, 0 ms] (11) QDP (12) QDPSizeChangeProof [EQUIVALENT, 0 ms] (13) YES (14) QDP (15) MNOCProof [EQUIVALENT, 0 ms] (16) QDP (17) NonLoopProof [COMPLETE, 33 ms] (18) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: g(tt, x, y) -> g(swap(x, y), s(x), s(y)) swap(0, y) -> tt swap(s(x), y) -> swap(x, s(y)) Q is empty. ---------------------------------------- (1) AAECC Innermost (EQUIVALENT) We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is swap(0, y) -> tt swap(s(x), y) -> swap(x, s(y)) The TRS R 2 is g(tt, x, y) -> g(swap(x, y), s(x), s(y)) The signature Sigma is {g_3} ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: g(tt, x, y) -> g(swap(x, y), s(x), s(y)) swap(0, y) -> tt swap(s(x), y) -> swap(x, s(y)) The set Q consists of the following terms: g(tt, x0, x1) swap(0, x0) swap(s(x0), x1) ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: G(tt, x, y) -> G(swap(x, y), s(x), s(y)) G(tt, x, y) -> SWAP(x, y) SWAP(s(x), y) -> SWAP(x, s(y)) The TRS R consists of the following rules: g(tt, x, y) -> g(swap(x, y), s(x), s(y)) swap(0, y) -> tt swap(s(x), y) -> swap(x, s(y)) The set Q consists of the following terms: g(tt, x0, x1) swap(0, x0) swap(s(x0), x1) We have to consider all minimal (P,Q,R)-chains. ----------------------------------------
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