TRS Standard pair #487067233

details

property	value
status	complete
benchmark	emmes-nonloop-ex6_2.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n182.star.cs.uiowa.edu
space	EEG_IJCAR_12

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	12.0579 seconds
cpu usage	32.6266
user time	31.8375
system time	0.78913
max virtual memory	3.7270812E7
max residence set size	1109356.0

stage attributes

key	value
starexec-result	NO

output

NO
proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml
# AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty


Termination w.r.t. Q of the given QTRS could be disproven:

(0) QTRS
(1) AAECC Innermost [EQUIVALENT, 0 ms]
(2) QTRS
(3) DependencyPairsProof [EQUIVALENT, 0 ms]
(4) QDP
(5) DependencyGraphProof [EQUIVALENT, 0 ms]
(6) AND
    (7) QDP
        (8) UsableRulesProof [EQUIVALENT, 0 ms]
        (9) QDP
        (10) QReductionProof [EQUIVALENT, 0 ms]
        (11) QDP
        (12) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (13) YES
    (14) QDP
        (15) UsableRulesProof [EQUIVALENT, 0 ms]
        (16) QDP
        (17) QReductionProof [EQUIVALENT, 0 ms]
        (18) QDP
        (19) MRRProof [EQUIVALENT, 0 ms]
        (20) QDP
        (21) DependencyGraphProof [EQUIVALENT, 0 ms]
        (22) TRUE
    (23) QDP
        (24) UsableRulesProof [EQUIVALENT, 0 ms]
        (25) QDP
        (26) QReductionProof [EQUIVALENT, 0 ms]
        (27) QDP
        (28) QDPSizeChangeProof [EQUIVALENT, 0 ms]
        (29) YES
    (30) QDP
        (31) MNOCProof [EQUIVALENT, 0 ms]
        (32) QDP
        (33) NonLoopProof [COMPLETE, 192 ms]
        (34) NO


----------------------------------------

(0)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   f(true, xs) -> f(isList(xs), append(cons(a, nil), xs))
   isList(nil) -> true
   isList(cons(x, xs)) -> isList(xs)
   append(xs, ys) -> appendAkk(reverse(xs), ys)
   appendAkk(nil, ys) -> ys
   appendAkk(cons(x, xs), ys) -> appendAkk(xs, cons(x, ys))
   reverse(nil) -> nil
   reverse(cons(x, xs)) -> append(reverse(xs), cons(x, nil))

Q is empty.

----------------------------------------

(1) AAECC Innermost (EQUIVALENT)
We have applied [NOC,AAECCNOC] to switch to innermost. The TRS R 1 is 
   isList(nil) -> true
   isList(cons(x, xs)) -> isList(xs)
   append(xs, ys) -> appendAkk(reverse(xs), ys)
   appendAkk(nil, ys) -> ys
   appendAkk(cons(x, xs), ys) -> appendAkk(xs, cons(x, ys))
   reverse(nil) -> nil
   reverse(cons(x, xs)) -> append(reverse(xs), cons(x, nil))

The TRS R 2 is 
   f(true, xs) -> f(isList(xs), append(cons(a, nil), xs))

The signature Sigma is {f_2}
----------------------------------------

(2)
Obligation:
Q restricted rewrite system:
The TRS R consists of the following rules:

   f(true, xs) -> f(isList(xs), append(cons(a, nil), xs))
   isList(nil) -> true
   isList(cons(x, xs)) -> isList(xs)
   append(xs, ys) -> appendAkk(reverse(xs), ys)
   appendAkk(nil, ys) -> ys
   appendAkk(cons(x, xs), ys) -> appendAkk(xs, cons(x, ys))
   reverse(nil) -> nil
   reverse(cons(x, xs)) -> append(reverse(xs), cons(x, nil))

The set Q consists of the following terms:

   f(true, x0)
   isList(nil)
   isList(cons(x0, x1))
   append(x0, x1)

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