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TRS Standard pair #487067592
details
property
value
status
complete
benchmark
#3.51.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n071.star.cs.uiowa.edu
space
AG01
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.482477 seconds
cpu usage
0.894247
user time
0.694171
system time
0.200076
max virtual memory
96176.0
max residence set size
59948.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: f(f(x)) -> f(c(f(x))) f(f(x)) -> f(d(f(x))) g(c(x)) -> x g(d(x)) -> x g(c(h(0()))) -> g(d(1())) g(c(1())) -> g(d(h(0()))) g(h(x)) -> g(x) Proof: Matrix Interpretation Processor: dim=3 interpretation: [0] [0] = [1] [0], [1 0 1] [c](x0) = [0 0 0]x0 [0 1 1] , [1 0 0] [g](x0) = [0 0 1]x0 [0 0 1] , [1 0 0] [h](x0) = [0 0 0]x0 [0 1 1] , [1 1 0] [0] [f](x0) = [0 0 0]x0 + [1] [0 0 0] [0], [0] [1] = [1] [0], [1 1 0] [d](x0) = [0 0 0]x0 [0 1 1] orientation: [1 1 0] [1] [1 1 0] [0] f(f(x)) = [0 0 0]x + [1] >= [0 0 0]x + [1] = f(c(f(x))) [0 0 0] [0] [0 0 0] [0] [1 1 0] [1] [1 1 0] [1] f(f(x)) = [0 0 0]x + [1] >= [0 0 0]x + [1] = f(d(f(x))) [0 0 0] [0] [0 0 0] [0] [1 0 1] g(c(x)) = [0 1 1]x >= x = x [0 1 1] [1 1 0] g(d(x)) = [0 1 1]x >= x = x [0 1 1] [1] [1] g(c(h(0()))) = [1] >= [1] = g(d(1())) [1] [1] [0] [0] g(c(1())) = [1] >= [1] = g(d(h(0()))) [1] [1] [1 0 0] [1 0 0] g(h(x)) = [0 1 1]x >= [0 0 1]x = g(x) [0 1 1] [0 0 1] problem: f(f(x)) -> f(d(f(x))) g(c(x)) -> x g(d(x)) -> x g(c(h(0()))) -> g(d(1())) g(c(1())) -> g(d(h(0()))) g(h(x)) -> g(x) Matrix Interpretation Processor: dim=3 interpretation: [0] [0] = [0] [0], [1 0 0] [1] [c](x0) = [0 0 0]x0 + [0] [0 1 1] [0], [1 0 0] [g](x0) = [0 0 1]x0 [0 0 1] , [1 0 0] [h](x0) = [0 0 0]x0 [0 0 1] , [1 1 0] [0] [f](x0) = [0 0 0]x0 + [1] [0 1 1] [0],
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