details

property	value
status	complete
benchmark	#3.47.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n180.star.cs.uiowa.edu
space	AG01

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.448703 seconds
cpu usage	0.720118
user time	0.531378
system time	0.18874
max virtual memory	96176.0
max residence set size	60260.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: f(x,c(y)) -> f(x,s(f(y,y))) f(s(x),y) -> f(x,s(c(y))) Proof: Matrix Interpretation Processor: dim=2 interpretation: [1 0] [2 2] [0] [f](x0, x1) = [0 0]x0 + [0 0]x1 + [2], [1 0] [0] [c](x0) = [2 2]x0 + [1], [1 0] [s](x0) = [0 0]x0 orientation: [1 0] [6 4] [2] [1 0] [6 4] [0] f(x,c(y)) = [0 0]x + [0 0]y + [2] >= [0 0]x + [0 0]y + [2] = f(x,s(f(y,y))) [1 0] [2 2] [0] [1 0] [2 0] [0] f(s(x),y) = [0 0]x + [0 0]y + [2] >= [0 0]x + [0 0]y + [2] = f(x,s(c(y))) problem: f(s(x),y) -> f(x,s(c(y))) Matrix Interpretation Processor: dim=3 interpretation: [1 1 1] [1 0 0] [f](x0, x1) = [0 1 1]x0 + [0 0 1]x1 [1 0 0] [0 0 0] , [1 0 0] [c](x0) = [0 0 1]x0 [0 0 0] , [1 0 0] [0] [s](x0) = [0 0 0]x0 + [0] [0 1 1] [1] orientation: [1 1 1] [1 0 0] [1] [1 1 1] [1 0 0] [0] f(s(x),y) = [0 1 1]x + [0 0 1]y + [1] >= [0 1 1]x + [0 0 1]y + [1] = f(x,s(c(y))) [1 0 0] [0 0 0] [0] [1 0 0] [0 0 0] [0] problem: Qed popout

output may be truncated. 'popout' for the full output.

job log

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actions

all output return to TRS Standard