details

property	value
status	complete
benchmark	4.40.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n177.star.cs.uiowa.edu
space	SK90

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	2.6656 seconds
cpu usage	6.72095
user time	6.44305
system time	0.2779
max virtual memory	1.8411188E7
max residence set size	387808.0

stage attributes

key	value
starexec-result	NO

output

NO proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be disproven: (0) QTRS (1) Overlay + Local Confluence [EQUIVALENT, 0 ms] (2) QTRS (3) DependencyPairsProof [EQUIVALENT, 0 ms] (4) QDP (5) TransformationProof [EQUIVALENT, 0 ms] (6) QDP (7) TransformationProof [EQUIVALENT, 0 ms] (8) QDP (9) MNOCProof [EQUIVALENT, 0 ms] (10) QDP (11) NonTerminationLoopProof [COMPLETE, 121 ms] (12) NO ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y Q is empty. ---------------------------------------- (1) Overlay + Local Confluence (EQUIVALENT) The TRS is overlay and locally confluent. By [NOC] we can switch to innermost. ---------------------------------------- (2) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y The set Q consists of the following terms: f(f(f(a, x0), x1), x2) f(f(b, x0), x1) f(c, x0) ---------------------------------------- (3) DependencyPairsProof (EQUIVALENT) Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. ---------------------------------------- (4) Obligation: Q DP problem: The TRS P consists of the following rules: F(f(f(a, x), y), z) -> F(f(x, z), f(y, z)) F(f(f(a, x), y), z) -> F(x, z) F(f(f(a, x), y), z) -> F(y, z) The TRS R consists of the following rules: f(f(f(a, x), y), z) -> f(f(x, z), f(y, z)) f(f(b, x), y) -> x f(c, y) -> y The set Q consists of the following terms: f(f(f(a, x0), x1), x2) f(f(b, x0), x1) f(c, x0) We have to consider all minimal (P,Q,R)-chains. ---------------------------------------- (5) TransformationProof (EQUIVALENT) By forward instantiating [JAR06] the rule F(f(f(a, x), y), z) -> F(x, z) we obtained the following new rules [LPAR04]: (F(f(f(a, f(f(a, y_0), y_1)), x1), x2) -> F(f(f(a, y_0), y_1), x2),F(f(f(a, f(f(a, y_0), y_1)), x1), x2) -> F(f(f(a, y_0), y_1), x2)) ---------------------------------------- (6) Obligation: Q DP problem: The TRS P consists of the following rules: popout

output may be truncated. 'popout' for the full output.

job log

popout

actions

all output return to TRS Standard