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TRS Standard pair #487067797
details
property
value
status
complete
benchmark
2.07.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n178.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.470697 seconds
cpu usage
0.82205
user time
0.639514
system time
0.182536
max virtual memory
96176.0
max residence set size
61068.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: f(0(),y) -> y f(x,0()) -> x f(i(x),y) -> i(x) f(f(x,y),z) -> f(x,f(y,z)) f(g(x,y),z) -> g(f(x,z),f(y,z)) f(1(),g(x,y)) -> x f(2(),g(x,y)) -> y Proof: DP Processor: DPs: f#(f(x,y),z) -> f#(y,z) f#(f(x,y),z) -> f#(x,f(y,z)) f#(g(x,y),z) -> f#(y,z) f#(g(x,y),z) -> f#(x,z) TRS: f(0(),y) -> y f(x,0()) -> x f(i(x),y) -> i(x) f(f(x,y),z) -> f(x,f(y,z)) f(g(x,y),z) -> g(f(x,z),f(y,z)) f(1(),g(x,y)) -> x f(2(),g(x,y)) -> y Subterm Criterion Processor: simple projection: pi(f#) = 0 problem: DPs: TRS: f(0(),y) -> y f(x,0()) -> x f(i(x),y) -> i(x) f(f(x,y),z) -> f(x,f(y,z)) f(g(x,y),z) -> g(f(x,z),f(y,z)) f(1(),g(x,y)) -> x f(2(),g(x,y)) -> y Qed
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