details

property	value
status	complete
benchmark	4.61.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n185.star.cs.uiowa.edu
space	SK90

run statistics

property	value
solver	muterm 6.0.3
configuration	default
runtime (wallclock)	7.84602 seconds
cpu usage	7.82298
user time	7.54213
system time	0.280845
max virtual memory	837960.0
max residence set size	96728.0

stage attributes

key	value
starexec-result	YES

output

YES Problem 1: (VAR v_NonEmpty:S x:S y:S z:S) (RULES bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 ) Problem 1: Innermost Equivalent Processor: -> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: BSORT(.(x:S,y:S)) -> BSORT(butlast(bubble(.(x:S,y:S)))) BSORT(.(x:S,y:S)) -> BUBBLE(.(x:S,y:S)) BSORT(.(x:S,y:S)) -> BUTLAST(bubble(.(x:S,y:S))) BSORT(.(x:S,y:S)) -> LAST(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(x:S,z:S)) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(y:S,z:S)) BUTLAST(.(x:S,.(y:S,z:S))) -> BUTLAST(.(y:S,z:S)) LAST(.(x:S,.(y:S,z:S))) -> LAST(.(y:S,z:S)) -> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 Problem 1: SCC Processor: -> Pairs: BSORT(.(x:S,y:S)) -> BSORT(butlast(bubble(.(x:S,y:S)))) BSORT(.(x:S,y:S)) -> BUBBLE(.(x:S,y:S)) BSORT(.(x:S,y:S)) -> BUTLAST(bubble(.(x:S,y:S))) BSORT(.(x:S,y:S)) -> LAST(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(x:S,z:S)) BUBBLE(.(x:S,.(y:S,z:S))) -> BUBBLE(.(y:S,z:S)) BUTLAST(.(x:S,.(y:S,z:S))) -> BUTLAST(.(y:S,z:S)) LAST(.(x:S,.(y:S,z:S))) -> LAST(.(y:S,z:S)) -> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) last(.(x:S,nil)) -> x:S last(nil) -> 0 ->Strongly Connected Components: ->->Cycle: ->->-> Pairs: LAST(.(x:S,.(y:S,z:S))) -> LAST(.(y:S,z:S)) ->->-> Rules: bsort(.(x:S,y:S)) -> last(.(bubble(.(x:S,y:S)),bsort(butlast(bubble(.(x:S,y:S)))))) bsort(nil) -> nil bubble(.(x:S,.(y:S,z:S))) -> if(<=(x:S,y:S),.(y:S,bubble(.(x:S,z:S))),.(x:S,bubble(.(y:S,z:S)))) bubble(.(x:S,nil)) -> .(x:S,nil) bubble(nil) -> nil butlast(.(x:S,.(y:S,z:S))) -> .(x:S,butlast(.(y:S,z:S))) butlast(.(x:S,nil)) -> nil butlast(nil) -> nil last(.(x:S,.(y:S,z:S))) -> last(.(y:S,z:S)) popout

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job log

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actions

all output return to TRS Standard