details

property	value
status	complete
benchmark	4.44.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n074.star.cs.uiowa.edu
space	SK90

run statistics

property	value
solver	ttt2-1.20
configuration	ttt2
runtime (wallclock)	0.383664 seconds
cpu usage	0.535457
user time	0.412895
system time	0.122562
max virtual memory	96176.0
max residence set size	57416.0

stage attributes

key	value
starexec-result	YES

output

YES Problem: f(h(x)) -> f(i(x)) g(i(x)) -> g(h(x)) h(a()) -> b() i(a()) -> b() Proof: Matrix Interpretation Processor: dim=1 interpretation: [a] = 4, [f](x0) = x0, [g](x0) = 2x0, [b] = 0, [h](x0) = 2x0 + 6, [i](x0) = 2x0 + 6 orientation: f(h(x)) = 2x + 6 >= 2x + 6 = f(i(x)) g(i(x)) = 4x + 12 >= 4x + 12 = g(h(x)) h(a()) = 14 >= 0 = b() i(a()) = 14 >= 0 = b() problem: f(h(x)) -> f(i(x)) g(i(x)) -> g(h(x)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [f](x0) = [0 0 1]x0 [0 0 0] , [1 1 0] [0] [g](x0) = [1 0 0]x0 + [1] [1 0 0] [0], [1 0 0] [0] [h](x0) = [0 0 0]x0 + [0] [0 0 0] [1], [1 0 0] [0] [i](x0) = [0 0 0]x0 + [1] [0 0 0] [0] orientation: [1 0 0] [1] [1 0 0] f(h(x)) = [0 0 0]x + [1] >= [0 0 0]x = f(i(x)) [0 0 0] [0] [0 0 0] [1 0 0] [1] [1 0 0] [0] g(i(x)) = [1 0 0]x + [1] >= [1 0 0]x + [1] = g(h(x)) [1 0 0] [0] [1 0 0] [0] problem: Qed popout

output may be truncated. 'popout' for the full output.

job log

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all output return to TRS Standard