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TRS Standard pair #487068185
details
property
value
status
complete
benchmark
4.52.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n072.star.cs.uiowa.edu
space
SK90
run statistics
property
value
solver
NTI-TC20-firstrun
configuration
Default 200
runtime (wallclock)
0.186048 seconds
cpu usage
0.238966
user time
0.193666
system time
0.0453
max virtual memory
113188.0
max residence set size
53060.0
stage attributes
key
value
starexec-result
YES
output
YES Prover = TRS(tech=GUIDED_UNF_TRIPLES, nb_unfoldings=unlimited, unfold_variables=false, max_nb_coefficients=12, max_nb_unfolded_rules=-1, strategy=LEFTMOST_NE) ** BEGIN proof argument ** All the DP problems were proved finite. As all the involved DP processors are sound, the TRS under analysis terminates. ** END proof argument ** ** BEGIN proof description ** ## Searching for a generalized rewrite rule (a rule whose right-hand side contains a variable that does not occur in the left-hand side)... No generalized rewrite rule found! ## Applying the DP framework... ## Round 1: ## DP problem: Dependency pairs = [s^#(f(_0,_1)) -> s^#(_1), s^#(f(_0,_1)) -> s^#(_0), s^#(g(_0,_1)) -> s^#(_0), s^#(g(_0,_1)) -> s^#(_1)] TRS = {s(a) -> a, s(s(_0)) -> _0, s(f(_0,_1)) -> f(s(_1),s(_0)), s(g(_0,_1)) -> g(s(_0),s(_1)), f(_0,a) -> _0, f(a,_0) -> _0, f(g(_0,_1),g(_2,_3)) -> g(f(_0,_2),f(_1,_3)), g(a,a) -> a} ## Trying with homeomorphic embeddings... Success! This DP problem is finite. ## DP problem: Dependency pairs = [f^#(g(_0,_1),g(_2,_3)) -> f^#(_0,_2), f^#(g(_0,_1),g(_2,_3)) -> f^#(_1,_3)] TRS = {s(a) -> a, s(s(_0)) -> _0, s(f(_0,_1)) -> f(s(_1),s(_0)), s(g(_0,_1)) -> g(s(_0),s(_1)), f(_0,a) -> _0, f(a,_0) -> _0, f(g(_0,_1),g(_2,_3)) -> g(f(_0,_2),f(_1,_3)), g(a,a) -> a} ## Trying with homeomorphic embeddings... Success! This DP problem is finite. ** END proof description ** Proof stopped at iteration 0 Number of unfolded rules generated by this proof = 0 Number of unfolded rules generated by all the parallel proofs = 0
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