details

property	value
status	complete
benchmark	4.20.xml
ran by	Akihisa Yamada
cpu timeout	1200 seconds
wallclock timeout	300 seconds
memory limit	137438953472 bytes
execution host	n178.star.cs.uiowa.edu
space	SK90

run statistics

property	value
solver	AProVE
configuration	standard
runtime (wallclock)	1.72394 seconds
cpu usage	3.73518
user time	3.57539
system time	0.159786
max virtual memory	1.8408912E7
max residence set size	240324.0

stage attributes

key	value
starexec-result	YES

output

YES proof of /export/starexec/sandbox/benchmark/theBenchmark.xml # AProVE Commit ID: 794c25de1cacf0d048858bcd21c9a779e1221865 marcel 20200619 unpublished dirty Termination w.r.t. Q of the given QTRS could be proven: (0) QTRS (1) QTRSRRRProof [EQUIVALENT, 57 ms] (2) QTRS (3) RisEmptyProof [EQUIVALENT, 0 ms] (4) YES ---------------------------------------- (0) Obligation: Q restricted rewrite system: The TRS R consists of the following rules: not(x) -> xor(x, true) or(x, y) -> xor(and(x, y), xor(x, y)) implies(x, y) -> xor(and(x, y), xor(x, true)) and(x, true) -> x and(x, false) -> false and(x, x) -> x xor(x, false) -> x xor(x, x) -> false and(xor(x, y), z) -> xor(and(x, z), and(y, z)) Q is empty. ---------------------------------------- (1) QTRSRRRProof (EQUIVALENT) Used ordering: Quasi precedence: or_2 > and_2 > [xor_2, false] implies_2 > [not_1, true] > [xor_2, false] implies_2 > and_2 > [xor_2, false] Status: not_1: multiset status xor_2: multiset status true: multiset status or_2: multiset status and_2: multiset status implies_2: multiset status false: multiset status With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: not(x) -> xor(x, true) or(x, y) -> xor(and(x, y), xor(x, y)) implies(x, y) -> xor(and(x, y), xor(x, true)) and(x, true) -> x and(x, false) -> false and(x, x) -> x xor(x, false) -> x xor(x, x) -> false and(xor(x, y), z) -> xor(and(x, z), and(y, z)) ---------------------------------------- (2) Obligation: Q restricted rewrite system: R is empty. Q is empty. ---------------------------------------- (3) RisEmptyProof (EQUIVALENT) The TRS R is empty. Hence, termination is trivially proven. ---------------------------------------- (4) YES popout

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all output return to TRS Standard