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TRS Standard pair #487068307
details
property
value
status
complete
benchmark
t013.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n192.star.cs.uiowa.edu
space
HirokawaMiddeldorp_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.541052 seconds
cpu usage
1.08125
user time
0.778996
system time
0.302252
max virtual memory
96176.0
max residence set size
61288.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: -(x,0()) -> x -(0(),s(y)) -> 0() -(s(x),s(y)) -> -(x,y) f(0()) -> 0() f(s(x)) -> -(s(x),g(f(x))) g(0()) -> s(0()) g(s(x)) -> -(s(x),f(g(x))) Proof: Matrix Interpretation Processor: dim=1 interpretation: [g](x0) = 4x0 + 1, [-](x0, x1) = x0 + x1, [f](x0) = 4x0, [0] = 0, [s](x0) = 6x0 + 1 orientation: -(x,0()) = x >= x = x -(0(),s(y)) = 6y + 1 >= 0 = 0() -(s(x),s(y)) = 6x + 6y + 2 >= x + y = -(x,y) f(0()) = 0 >= 0 = 0() f(s(x)) = 24x + 4 >= 22x + 2 = -(s(x),g(f(x))) g(0()) = 1 >= 1 = s(0()) g(s(x)) = 24x + 5 >= 22x + 5 = -(s(x),f(g(x))) problem: -(x,0()) -> x f(0()) -> 0() g(0()) -> s(0()) g(s(x)) -> -(s(x),f(g(x))) Matrix Interpretation Processor: dim=1 interpretation: [g](x0) = 2x0 + 5, [-](x0, x1) = x0 + x1 + 5, [f](x0) = x0, [0] = 0, [s](x0) = 2x0 + 5 orientation: -(x,0()) = x + 5 >= x = x f(0()) = 0 >= 0 = 0() g(0()) = 5 >= 5 = s(0()) g(s(x)) = 4x + 15 >= 4x + 15 = -(s(x),f(g(x))) problem: f(0()) -> 0() g(0()) -> s(0()) g(s(x)) -> -(s(x),f(g(x))) Matrix Interpretation Processor: dim=1 interpretation: [g](x0) = 2x0 + 5, [-](x0, x1) = x0 + x1 + 4, [f](x0) = x0, [0] = 0, [s](x0) = 2x0 + 5 orientation: f(0()) = 0 >= 0 = 0() g(0()) = 5 >= 5 = s(0()) g(s(x)) = 4x + 15 >= 4x + 14 = -(s(x),f(g(x))) problem: f(0()) -> 0() g(0()) -> s(0()) Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [1] [g](x0) = [0 0 0]x0 + [0] [0 0 0] [0], [1 0 0] [1] [f](x0) = [0 0 0]x0 + [0] [0 0 0] [0], [0]
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