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TRS Standard pair #487068409
details
property
value
status
complete
benchmark
recursion-10.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n173.star.cs.uiowa.edu
space
TCT_12
run statistics
property
value
solver
muterm 6.0.3
configuration
default
runtime (wallclock)
0.038712 seconds
cpu usage
0.039309
user time
0.022301
system time
0.017008
max virtual memory
113188.0
max residence set size
9456.0
stage attributes
key
value
starexec-result
YES
output
YES Problem 1: (VAR v_NonEmpty:S x:S y:S) (RULES f_0(x:S) -> a f_1(x:S) -> g_1(x:S,x:S) f_10(x:S) -> g_10(x:S,x:S) f_2(x:S) -> g_2(x:S,x:S) f_3(x:S) -> g_3(x:S,x:S) f_4(x:S) -> g_4(x:S,x:S) f_5(x:S) -> g_5(x:S,x:S) f_6(x:S) -> g_6(x:S,x:S) f_7(x:S) -> g_7(x:S,x:S) f_8(x:S) -> g_8(x:S,x:S) f_9(x:S) -> g_9(x:S,x:S) g_1(s(x:S),y:S) -> b(f_0(y:S),g_1(x:S,y:S)) g_10(s(x:S),y:S) -> b(f_9(y:S),g_10(x:S,y:S)) g_2(s(x:S),y:S) -> b(f_1(y:S),g_2(x:S,y:S)) g_3(s(x:S),y:S) -> b(f_2(y:S),g_3(x:S,y:S)) g_4(s(x:S),y:S) -> b(f_3(y:S),g_4(x:S,y:S)) g_5(s(x:S),y:S) -> b(f_4(y:S),g_5(x:S,y:S)) g_6(s(x:S),y:S) -> b(f_5(y:S),g_6(x:S,y:S)) g_7(s(x:S),y:S) -> b(f_6(y:S),g_7(x:S,y:S)) g_8(s(x:S),y:S) -> b(f_7(y:S),g_8(x:S,y:S)) g_9(s(x:S),y:S) -> b(f_8(y:S),g_9(x:S,y:S)) ) Problem 1: Innermost Equivalent Processor: -> Rules: f_0(x:S) -> a f_1(x:S) -> g_1(x:S,x:S) f_10(x:S) -> g_10(x:S,x:S) f_2(x:S) -> g_2(x:S,x:S) f_3(x:S) -> g_3(x:S,x:S) f_4(x:S) -> g_4(x:S,x:S) f_5(x:S) -> g_5(x:S,x:S) f_6(x:S) -> g_6(x:S,x:S) f_7(x:S) -> g_7(x:S,x:S) f_8(x:S) -> g_8(x:S,x:S) f_9(x:S) -> g_9(x:S,x:S) g_1(s(x:S),y:S) -> b(f_0(y:S),g_1(x:S,y:S)) g_10(s(x:S),y:S) -> b(f_9(y:S),g_10(x:S,y:S)) g_2(s(x:S),y:S) -> b(f_1(y:S),g_2(x:S,y:S)) g_3(s(x:S),y:S) -> b(f_2(y:S),g_3(x:S,y:S)) g_4(s(x:S),y:S) -> b(f_3(y:S),g_4(x:S,y:S)) g_5(s(x:S),y:S) -> b(f_4(y:S),g_5(x:S,y:S)) g_6(s(x:S),y:S) -> b(f_5(y:S),g_6(x:S,y:S)) g_7(s(x:S),y:S) -> b(f_6(y:S),g_7(x:S,y:S)) g_8(s(x:S),y:S) -> b(f_7(y:S),g_8(x:S,y:S)) g_9(s(x:S),y:S) -> b(f_8(y:S),g_9(x:S,y:S)) -> The term rewriting system is non-overlaping or locally confluent overlay system. Therefore, innermost termination implies termination. Problem 1: Dependency Pairs Processor: -> Pairs: F_1(x:S) -> G_1(x:S,x:S) F_10(x:S) -> G_10(x:S,x:S) F_2(x:S) -> G_2(x:S,x:S) F_3(x:S) -> G_3(x:S,x:S) F_4(x:S) -> G_4(x:S,x:S) F_5(x:S) -> G_5(x:S,x:S) F_6(x:S) -> G_6(x:S,x:S) F_7(x:S) -> G_7(x:S,x:S) F_8(x:S) -> G_8(x:S,x:S) F_9(x:S) -> G_9(x:S,x:S) G_1(s(x:S),y:S) -> F_0(y:S) G_1(s(x:S),y:S) -> G_1(x:S,y:S) G_10(s(x:S),y:S) -> F_9(y:S) G_10(s(x:S),y:S) -> G_10(x:S,y:S) G_2(s(x:S),y:S) -> F_1(y:S) G_2(s(x:S),y:S) -> G_2(x:S,y:S) G_3(s(x:S),y:S) -> F_2(y:S) G_3(s(x:S),y:S) -> G_3(x:S,y:S) G_4(s(x:S),y:S) -> F_3(y:S) G_4(s(x:S),y:S) -> G_4(x:S,y:S) G_5(s(x:S),y:S) -> F_4(y:S) G_5(s(x:S),y:S) -> G_5(x:S,y:S) G_6(s(x:S),y:S) -> F_5(y:S) G_6(s(x:S),y:S) -> G_6(x:S,y:S) G_7(s(x:S),y:S) -> F_6(y:S) G_7(s(x:S),y:S) -> G_7(x:S,y:S) G_8(s(x:S),y:S) -> F_7(y:S) G_8(s(x:S),y:S) -> G_8(x:S,y:S) G_9(s(x:S),y:S) -> F_8(y:S) G_9(s(x:S),y:S) -> G_9(x:S,y:S) -> Rules: f_0(x:S) -> a f_1(x:S) -> g_1(x:S,x:S) f_10(x:S) -> g_10(x:S,x:S) f_2(x:S) -> g_2(x:S,x:S) f_3(x:S) -> g_3(x:S,x:S) f_4(x:S) -> g_4(x:S,x:S) f_5(x:S) -> g_5(x:S,x:S) f_6(x:S) -> g_6(x:S,x:S)
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