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TRS Standard pair #487068867
details
property
value
status
complete
benchmark
rta2.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n186.star.cs.uiowa.edu
space
AProVE_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.388511 seconds
cpu usage
0.535068
user time
0.393454
system time
0.141614
max virtual memory
96176.0
max residence set size
58008.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: f(s(x),y) -> f(x,s(x)) f(x,s(y)) -> f(y,x) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 1 1] [1 1 0] [1] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 + [0] [0 0 0] [0 0 0] [0], [1 1 1] [1] [s](x0) = [1 1 1]x0 + [0] [1 1 1] [0] orientation: [3 3 3] [1 1 0] [2] [3 3 3] [2] f(s(x),y) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0] = f(x,s(x)) [0 0 0] [0 0 0] [0] [0 0 0] [0] [1 1 1] [2 2 2] [2] [1 1 0] [1 1 1] [1] f(x,s(y)) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x + [0 0 0]y + [0] = f(y,x) [0 0 0] [0 0 0] [0] [0 0 0] [0 0 0] [0] problem: f(s(x),y) -> f(x,s(x)) Matrix Interpretation Processor: dim=3 interpretation: [1 0 1] [1 0 0] [f](x0, x1) = [0 0 0]x0 + [0 0 0]x1 [0 0 0] [0 0 0] , [1 0 0] [0] [s](x0) = [0 0 0]x0 + [0] [1 0 1] [1] orientation: [2 0 1] [1 0 0] [1] [2 0 1] f(s(x),y) = [0 0 0]x + [0 0 0]y + [0] >= [0 0 0]x = f(x,s(x)) [0 0 0] [0 0 0] [0] [0 0 0] problem: Qed
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