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TRS Standard pair #487069277
details
property
value
status
complete
benchmark
lescanne.xml
ran by
Akihisa Yamada
cpu timeout
1200 seconds
wallclock timeout
300 seconds
memory limit
137438953472 bytes
execution host
n177.star.cs.uiowa.edu
space
Rubio_04
run statistics
property
value
solver
ttt2-1.20
configuration
ttt2
runtime (wallclock)
0.405175 seconds
cpu usage
0.589767
user time
0.448832
system time
0.140935
max virtual memory
96176.0
max residence set size
57740.0
stage attributes
key
value
starexec-result
YES
output
YES Problem: div(X,e()) -> i(X) i(div(X,Y)) -> div(Y,X) div(div(X,Y),Z) -> div(Y,div(i(X),Z)) Proof: Matrix Interpretation Processor: dim=3 interpretation: [1 0 0] [div](x0, x1) = [0 0 1]x0 + x1 [0 1 0] , [1] [e] = [0] [0], [1 0 0] [i](x0) = [0 0 1]x0 [0 1 0] orientation: [1 0 0] [1] [1 0 0] div(X,e()) = [0 0 1]X + [0] >= [0 0 1]X = i(X) [0 1 0] [0] [0 1 0] [1 0 0] [1 0 0] i(div(X,Y)) = X + [0 0 1]Y >= X + [0 0 1]Y = div(Y,X) [0 1 0] [0 1 0] [1 0 0] [1 0 0] div(div(X,Y),Z) = X + [0 0 1]Y + Z >= X + [0 0 1]Y + Z = div(Y,div(i(X),Z)) [0 1 0] [0 1 0] problem: i(div(X,Y)) -> div(Y,X) div(div(X,Y),Z) -> div(Y,div(i(X),Z)) Matrix Interpretation Processor: dim=1 interpretation: [div](x0, x1) = 4x0 + x1 + 4, [i](x0) = 4x0 + 1 orientation: i(div(X,Y)) = 16X + 4Y + 17 >= X + 4Y + 4 = div(Y,X) div(div(X,Y),Z) = 16X + 4Y + Z + 20 >= 16X + 4Y + Z + 12 = div(Y,div(i(X),Z)) problem: Qed
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